Back-counting within the same year: If March 2, 1994 was Wednesday, what day of the week was January 25, 1994?
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AWednesday
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BThursday
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CTuesday
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DMonday
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ENone of these
Answer
Correct Answer: Tuesday
Explanation
Introduction / Context:To move between two dates in the same year, count the number of days between them and reduce modulo 7. Here, we go backward from a known Wednesday (Mar 2) to a January date, so we subtract the appropriate offset.
Given Data / Assumptions:
- Mar 2, 1994 = Wednesday.
- 1994 is not a leap year (no Feb 29).
Concept / Approach:Compute days from Jan 25 to Mar 2 and reduce mod 7. Since the target (Jan 25) precedes the reference (Mar 2), move backward by that many days.
Step-by-Step Solution:
Jan 25 → Jan 31: 6 days.Full February (non-leap): 28 days.Mar 1 → Mar 2: 1 day (or include both days beyond Jan 31 as 30 total; either way total is 36).Total = 6 + 28 + 2 = 36 days ≡ 1 (mod 7).Therefore Jan 25 is one weekday earlier than Mar 2 ⇒ Tuesday.Verification / Alternative check:Wednesday minus 1 day = Tuesday; the arithmetic agrees with 36 ≡ 1.
Why Other Options Are Wrong:Wednesday/Thursday/Monday represent 0/+2/−2 shifts, which do not match 36 ≡ 1.
Common Pitfalls:Mistally of days in February or off-by-one when counting inclusive/exclusive endpoints; always reduce mod 7.
Final Answer:Tuesday