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Stress distribution in simple bending of beams Under the assumptions of simple (Euler–Bernoulli) bending, how does normal bending stress vary from the neutral axis to the outer fibers? Choose the correct variation.

Difficulty: Easy

Correct Answer: linearly

Explanation:

Concept
From σ = M y / I, the bending stress is proportional to distance y from the neutral axis. Hence it varies linearly, zero at the NA and maximum at the extreme fibers.


Final Answer
linearly

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