Rhombus — Perimeter from Diagonals: If the diagonals of a rhombus are 4.8 cm and 1.4 cm, find the perimeter of the rhombus (in cm).
Aptitude
Area
Difficulty: Easy
Choose an option
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A5 cm
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B10 cm
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C12 cm
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D20 cm
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E8 cm
Answer
Correct Answer: 10 cm
Explanation
Introduction / Context:In a rhombus, diagonals are perpendicular bisectors. Each side equals the hypotenuse of a right triangle with legs equal to half the diagonals. Once one side is known, the perimeter is four times the side length.
Given Data / Assumptions:
- d1 = 4.8 cm ⇒ d1/2 = 2.4 cm
- d2 = 1.4 cm ⇒ d2/2 = 0.7 cm
- Side s = √[(d1/2)^2 + (d2/2)^2]
- Perimeter P = 4s
Concept / Approach:Apply the Pythagorean theorem to the half-diagonals right triangle to compute the rhombus side, then multiply by 4 for the perimeter. Keep decimals precise to avoid rounding errors.
Step-by-Step Solution:
s = √(2.4^2 + 0.7^2) = √(5.76 + 0.49) = √6.25 = 2.5 cm.Perimeter P = 4 * 2.5 = 10 cm.Verification / Alternative check:
A rhombus with equal sides and perpendicular diagonals is consistent: s computed from halves returns an integer perimeter 10 cm.Why Other Options Are Wrong:
- 5 cm equals the side, not the perimeter/2.
- 12 cm and 20 cm overestimate s.
- 8 cm underestimates P.
Common Pitfalls:
- Using full diagonals instead of halves within Pythagoras.
Final Answer:10 cm.