Question 1

In this letter based odd one out reasoning question, select the letter pair that does not follow the same alphabetical spacing pattern as the pairs WZ, FG, UX and OR.

Accepted Answer

Introduction / Context:This is an alphabet pattern odd one out question from verbal reasoning. You are given four two letter groups and you need to identify which pair does not follow the same spacing pattern in terms of alphabetical positions. Such questions help test the candidate ability to quickly map letters to their positions in the English alphabet and recognize consistent jumps or differences between letters.Given Data / Assumptions: The given letter pairs are WZ, FG, UX and OR. The English alphabet is assumed to be A to Z with positions from 1 to 26. We consider the forward direction of the alphabet for counting differences. Concept / Approach:The general approach is to convert each letter to its alphabetical position and then compute the numerical difference between the first and second letter of each pair. If three pairs have the same difference and one pair has a different difference, the one that breaks the pattern is the odd one out.Step-by-Step Solution:Step 1: For WZ, W is the 23rd letter and Z is the 26th letter. Difference = 26 - 23 = 3.Step 2: For FG, F is the 6th letter and G is the 7th letter. Difference = 7 - 6 = 1.Step 3: For UX, U is the 21st letter and X is the 24th letter. Difference = 24 - 21 = 3.Step 4: For OR, O is the 15th letter and R is the 18th letter. Difference = 18 - 15 = 3.Step 5: We observe that WZ, UX and OR each have a difference of 3 between the first and second letter, while FG has a difference of only 1. Hence FG does not follow the same pattern as the other three.Verification / Alternative check:An alternative way is to mentally count the letters: W, X, Y, Z involves three steps from W to Z; U, V, W, X also gives three steps from U to X; O, P, Q, R gives three steps from O to R. For F to G there is only one step. This re confirms that FG is the only pair with a difference of 1, whereas the others have a difference of 3.Why Other Options Are Wrong:WZ is not the odd one out because it has a letter gap of 3, which matches UX and OR. UX is also not the odd one out since it follows the same +3 pattern in the alphabet as WZ and OR. OR is not the odd one out because it again maintains the three step difference between letters, consistent with WZ and UX. Common Pitfalls:Students sometimes focus on whether letters are near the start or end of the alphabet or on whether the pair contains vowels or consonants. These ideas do not give a consistent pattern in this question. The key is to focus on the numerical difference between positions in the alphabet. Confusing forward and backward counting or miscounting the number of letters between can also cause mistakes. Practicing mapping letters to numbers improves speed and accuracy in such problems.Final Answer:The only letter pair that has a difference of 1 instead of 3 is FG, so FG is the odd one out.

Question 2

In this number based odd one out question, you must select the unique number from 2378, 9122, 1517 and 2345 by analyzing the pattern in the sum of their digits.

Accepted Answer

Introduction / Context:This is a numerical odd one out question where the objective is to choose the number that does not satisfy a certain pattern in its digit sum. Problems like this test a candidate ability to observe properties of numbers, such as sum of digits, parity, or divisibility. Here, the standard trick is to compute the sum of the digits of each number and check for a consistent pattern among most of them.Given Data / Assumptions: The given four numbers are 2378, 9122, 1517 and 2345. We work with the base 10 representation of each number and inspect individual digits. We assume that the intended pattern is based on the sum of digits. Concept / Approach:Digit sum is a very common tool to identify patterns in odd one out questions, especially when numbers have several digits but nothing obviously special like being prime or perfect squares. The plan is to add the digits of each number and then compare the results. If three numbers share the same digit sum and one number produces a different digit sum, then that number is the odd one out.Step-by-Step Solution:Step 1: For 2378, the digits are 2, 3, 7 and 8. Sum = 2 + 3 + 7 + 8 = 20.Step 2: For 9122, the digits are 9, 1, 2 and 2. Sum = 9 + 1 + 2 + 2 = 14.Step 3: For 1517, the digits are 1, 5, 1 and 7. Sum = 1 + 5 + 1 + 7 = 14.Step 4: For 2345, the digits are 2, 3, 4 and 5. Sum = 2 + 3 + 4 + 5 = 14.Step 5: We observe that three numbers, 9122, 1517 and 2345, all have a digit sum of 14, whereas 2378 has a digit sum of 20. Thus 2378 does not fit the common digit sum pattern.Verification / Alternative check:You can re add the digits quickly to verify there was no arithmetic mistake. Another check is to use divisibility by 9 or 3, since the digit sum mod 9 gives the remainder on division by 9. All of 9122, 1517 and 2345 share the same digit sum, so they also share the same remainder when divided by 9, while 2378 differs. This reinforces that 2378 stands apart according to digit sum criteria.Why Other Options Are Wrong:9122 is not the odd one out because its digit sum is 14, the same as 1517 and 2345. 1517 is also not unique, as it shares a digit sum of 14 with 9122 and 2345. 2345 again has a digit sum of 14, so it conforms to the dominant pattern. Common Pitfalls:A common mistake is to look for more complicated properties such as prime status or factors, which can waste time. Another error is miscalculating digit sums, especially when doing mental arithmetic quickly. Candidates should add digits carefully and double check quickly. In many aptitude exams, simple digit sum patterns like this are frequent, so practicing them helps build speed and accuracy.Final Answer:The only number whose digits sum to 20 instead of 14 is 2378, so 2378 is the odd one out.

Question 3

In this basic divisibility based odd one out question, you must choose the number that is not a multiple of 8 from the set of numbers 56, 72, 90 and 64.

Accepted Answer

Introduction / Context:This question belongs to the number system and divisibility category in aptitude. You are required to identify which number does not share the same property of being a multiple of 8. Such questions build fluency in mental arithmetic and knowledge of common multiplication tables, which are critical for many competitive exams.Given Data / Assumptions: The numbers are 56, 72, 90 and 64. We assume standard arithmetic in base 10. The suspected pattern is that three numbers are multiples of 8, and one is not. Concept / Approach:A multiple of 8 can be written as 8 * n for some integer n. For two and three digit numbers, you can check quickly by dividing or by remembering the 8 times table. The approach is to test each number for divisibility by 8 and identify which one fails this test. The number that is not divisible by 8 will be the odd one out.Step-by-Step Solution:Step 1: Check 56. 8 * 7 = 56, so 56 is a multiple of 8.Step 2: Check 72. 8 * 9 = 72, so 72 is a multiple of 8.Step 3: Check 64. 8 * 8 = 64, so 64 is a multiple of 8.Step 4: Check 90. When we divide 90 by 8 we get 11.25, which is not an integer. Therefore, 90 is not a multiple of 8.Step 5: Since 56, 72 and 64 are exact multiples of 8 and 90 is not, 90 is the odd one out.Verification / Alternative check:Another verification approach is to use remainders. Compute 56 mod 8, 72 mod 8 and 64 mod 8, which all give 0. For 90 mod 8, the remainder is 2, confirming that it is not divisible by 8. This matches the earlier conclusion derived from direct multiplication table knowledge.Why Other Options Are Wrong:56 is not the odd one out because it is 7 times 8 and clearly a multiple of 8. 72 is not the odd one out as it equals 9 times 8 and fits the common pattern. 64 is also not the odd one out because it is 8 times 8, another standard multiple of 8. Common Pitfalls:Some learners may look only at whether a number is even, but all four numbers given here are even. Being even is not enough; the focus must be on being a multiple of 8 specifically. Another mistake is performing division too quickly and miscalculating the quotient for 90. Remember that 8 * 11 = 88 and 8 * 12 = 96, so there is no whole number n for which 8 * n = 90. Careful mental calculation prevents such errors.Final Answer:The only number that is not a multiple of 8 is 90, so 90 is the odd one out.

Question 4

In this vocabulary based odd one out question, you must select the word whose meaning is opposite in sense to the other three words Adamant, Stubborn, Tenacious and Lenient.

Accepted Answer

Introduction / Context:This is a verbal ability and vocabulary question that asks you to find the odd one out among four English words. The main skill tested is recognizing synonyms and antonyms. Three of the words express a similar idea, while one word expresses an opposite or significantly different idea. Such questions are commonly used in aptitude tests to check word meaning and nuance.Given Data / Assumptions: The words given are Adamant, Stubborn, Tenacious and Lenient. We assume general English usage and standard dictionary meanings. The goal is to group words by similarity of meaning. Concept / Approach:The strategy is to understand the meanings of all four words. Adamant, Stubborn and Tenacious all indicate a strong unwillingness to change one opinion or an ability to hold firmly to a position or goal. Lenient, however, means tolerant, permissive or not strict. Thus, Lenient represents the opposite attitude in comparison to the other three words, which describe a kind of firm or unyielding behavior.Step-by-Step Solution:Step 1: Adamant describes someone who is firm, unshakable and not willing to change opinions or decisions easily.Step 2: Stubborn also refers to a person who refuses to change their mind or behavior, often even when it is unreasonable to stay fixed.Step 3: Tenacious means holding on firmly, showing great determination or persistence, which again reflects a resolute and firm attitude.Step 4: Lenient means mild, tolerant, soft or permissive. A lenient person is flexible and less strict in enforcing rules or demands.Step 5: Clearly, Adamant, Stubborn and Tenacious all describe firmness and rigidity, while Lenient describes the opposite, a more forgiving and flexible nature. Therefore, Lenient is the odd one out.Verification / Alternative check:To verify, you can think of simple antonym pairs. The opposite of strict, firm or harsh is lenient or gentle. Since Adamant, Stubborn and Tenacious cluster around firmness, their natural opposite would be Lenient. Thus, looking at common usage and dictionary definitions strongly confirms that Lenient is the only word that does not belong with the others.Why Other Options Are Wrong:Adamant is not the odd one out because its meaning of being unyielding aligns closely with Stubborn and Tenacious. Stubborn also fits the firm and unchanging theme and therefore is not unique among the options. Tenacious, which conveys determination and firm grip, also belongs in the same meaning group as Adamant and Stubborn. Common Pitfalls:Students sometimes confuse Tenacious with a positive quality and Stubborn with a negative one, but both still indicate firmness. The odd one out is not chosen based on positive or negative connotation but on similarity of meaning. Another mistake is to think that Adamant is different because it is less commonly used, but vocabulary frequency is not relevant here; meaning is the key criterion.Final Answer:The only word that expresses a contrasting idea to the other three is Lenient, so Lenient is the odd one out.

Question 5

In this alphabet sequence odd one out question, select the triplet of letters that does not follow the same pattern of +2 and +3 jumps in alphabetical order among XAD, PRU, JLO and ACF.

Accepted Answer

Introduction / Context:This is a letter sequence odd one out question from verbal reasoning. You are given four three letter groups and must find which group does not follow the same consistent pattern of jumps in the alphabet. These types of questions strengthen candidates ability to map letters to positions and quickly recognize recurring patterns in sequences.Given Data / Assumptions: The letter triplets are XAD, PRU, JLO and ACF. We use the English alphabet positions: A = 1, B = 2, ..., Z = 26. The intended pattern compares the differences between consecutive letters in each triplet. Concept / Approach:The method is to convert each letter to its alphabetical position and then look at the numerical difference between the first and second letter, and between the second and third letter. If three triplets show the same pattern of differences and one does not, that non matching triplet is the odd one out.Step-by-Step Solution:Step 1: For PRU: P is 16, R is 18, U is 21. Differences are 18 - 16 = 2 and 21 - 18 = 3.Step 2: For JLO: J is 10, L is 12, O is 15. Differences are 12 - 10 = 2 and 15 - 12 = 3.Step 3: For ACF: A is 1, C is 3, F is 6. Differences are 3 - 1 = 2 and 6 - 3 = 3.Step 4: For XAD: X is 24, A is 1, D is 4. Differences if we move forward through the alphabet are 1 - 24 (wrapping around) and 4 - 1, which do not create the consistent pattern of +2 and +3. Instead, XAD breaks the smooth ascending pattern seen in the other triplets.Step 5: Since PRU, JLO and ACF each follow the pattern of +2 then +3 in alphabetical positions, and XAD does not follow this pattern, XAD is the odd one out.Verification / Alternative check:An alternative quick view is to treat PRU, JLO and ACF as sequences that step forward by 2, then by 3 letters. For PRU, from P to R we jump Q then R (two steps) and from R to U we jump S, T, U (three steps). Similar logic applies to J to L to O and A to C to F. XAD is irregular and does not form a smooth forward stepping sequence, confirming it as the odd one out.Why Other Options Are Wrong:PRU is not the odd one out because it shows a consistent +2, +3 forward stepping pattern. JLO also matches this +2, +3 pattern in the alphabet and therefore aligns with PRU and ACF. ACF follows the same rule of moving two steps forward and then three steps forward, so it clearly belongs with PRU and JLO. Common Pitfalls:One common error is to consider letter frequency in English words or to look for hidden words instead of focusing on alphabetical positions. Another mistake is ignoring the direction of movement in the alphabet and not noticing that letters in XAD break the regular progression. To avoid these issues, always convert letters to numerical positions and systematically inspect the differences.Final Answer:The only triplet that does not follow the pattern of +2 and then +3 in alphabetical order is XAD, so XAD is the odd one out.

Question 6

In this number pattern odd one out question, choose the number that does not satisfy the relation where the product of the first two digits equals the third digit among 325, 428, 326 and 177.

Accepted Answer

Introduction / Context:This question tests numerical pattern recognition within three digit numbers. You are asked to identify which number does not follow the same rule that connects its digits. Such questions are common in reasoning tests to measure how quickly candidates can discover hidden relationships among digits of a number.Given Data / Assumptions: The numbers given are 325, 428, 326 and 177. We consider the first, second and third digit of each number separately. The suspected pattern is a simple arithmetic relationship among the digits. Concept / Approach:The key idea is to inspect whether there is a consistent rule, such as the third digit being the sum or product of the first two digits. We test each possibility. On inspection, we find that for three of the numbers, the third digit equals the product of the first two digits. The number that fails this rule will be the odd one out.Step-by-Step Solution:Step 1: For 428, the digits are 4, 2 and 8. Product of first two digits: 4 * 2 = 8, which equals the third digit.Step 2: For 326, the digits are 3, 2 and 6. Product of first two digits: 3 * 2 = 6, which equals the third digit.Step 3: For 177, the digits are 1, 7 and 7. Product of first two digits: 1 * 7 = 7, which again matches the third digit.Step 4: For 325, the digits are 3, 2 and 5. Product of first two digits: 3 * 2 = 6, which does not equal the third digit 5.Step 5: Since 428, 326 and 177 follow the pattern third digit = first digit * second digit, and 325 does not, 325 is the odd one out.Verification / Alternative check:You can quickly re verify by re computing the products: 4 * 2 = 8, 3 * 2 = 6 and 1 * 7 = 7, all matching their respective last digits, while 3 * 2 = 6 does not match the last digit 5 in 325. No rounding or other adjustment is needed, so the pattern is very clear and consistent.Why Other Options Are Wrong:428 is not the odd one out because it perfectly fits the rule third digit = product of first two digits. 326 also satisfies this digit product rule and therefore belongs with 428 and 177. 177 follows the same pattern, since 1 * 7 = 7, which equals the last digit, so it is not unique. Common Pitfalls:A typical mistake is to first try sum based rules, like checking if the third digit is the sum of the first two digits, and then giving up when sums do not match. Another pitfall is to check more complicated relationships without testing the obvious product rule. To succeed in these questions, candidates should systematically try simple operations addition, subtraction and multiplication on digits.Final Answer:The only number that does not satisfy the pattern third digit = first digit * second digit is 325, so 325 is the odd one out.

Question 7

In this digit pattern odd one out question, identify the number whose digits are not all distinct among 532, 413, 111 and 541.

Accepted Answer

Introduction / Context:This reasoning question involves recognizing a simple digit pattern. The task is to select the number that does not share the same property regarding distinct digits as the others. Odd one out problems using digit repetition are common because they are easy to understand yet still require careful observation.Given Data / Assumptions: The numbers given are 532, 413, 111 and 541. We inspect the digits of each number individually. The suspected pattern is based on whether digits repeat within a number. Concept / Approach:The idea is to see whether all digits in a number are distinct or whether some digit is repeated. If three of the numbers have all unique digits, and one number has repeating digits, then the number with repeating digits is the odd one out. This is a direct and intuitive property that does not require any heavy arithmetic.Step-by-Step Solution:Step 1: For 532, the digits are 5, 3 and 2. All three digits are different.Step 2: For 413, the digits are 4, 1 and 3. Again, all three digits are distinct.Step 3: For 541, the digits are 5, 4 and 1. All three digits are distinct here as well.Step 4: For 111, the digits are 1, 1 and 1. All three digits are the same, so there is complete repetition.Step 5: Since 532, 413 and 541 each have distinct digits, while 111 consists of the same digit repeated three times, 111 clearly stands out as the odd one out.Verification / Alternative check:An alternative method is to count the number of distinct digits in each number. The distinct digit count is 3 for 532, 3 for 413, 3 for 541 and only 1 for 111. Therefore, 111 is the only number with fewer than 3 distinct digits, confirming it as the unique case in the group.Why Other Options Are Wrong:532 is not the odd one out because its digits are all different and follow the same pattern as 413 and 541. 413 is also not unique, since it features three distinct digits just like 532 and 541. 541 again has three different digits and therefore belongs together with 532 and 413. Common Pitfalls:Sometimes candidates look for complex arithmetic properties such as divisibility or prime status and miss the simple digit repetition pattern. Another pitfall is to overlook that all digits in 111 are the same, which is visually obvious but can be ignored when solving too quickly. It is always helpful to first check for simple and visible properties such as repetition, parity and digit count before attempting more complex rules.Final Answer:The only number that has repeating digits instead of distinct digits is 111, so 111 is the odd one out.

Question 8

In this general knowledge odd one out question, choose the country name that does not belong to the Indian subcontinent region among America, India, Bangladesh and Pakistan.

Accepted Answer

Introduction / Context:This odd one out question falls under basic geography and general knowledge. The task is to determine which country among the given options does not belong to the same regional grouping. Questions like this are common in competitive exams to test awareness of global and regional geography.Given Data / Assumptions: The country names given are America, India, Bangladesh and Pakistan. America here represents the United States of America. We consider the Indian subcontinent region for classification. Concept / Approach:The Indian subcontinent usually refers to a region in South Asia that includes countries such as India, Pakistan, Bangladesh, Sri Lanka, Nepal, Bhutan and sometimes others. In this group, India, Bangladesh and Pakistan are clearly part of the Indian subcontinent. The United States of America is in North America and does not belong to this regional grouping. Therefore, the country that does not fit the regional category is the odd one out.Step-by-Step Solution:Step 1: Identify India as a major country in South Asia and a key part of the Indian subcontinent.Step 2: Identify Bangladesh as another South Asian country that was previously part of undivided India and is also in the Indian subcontinent.Step 3: Identify Pakistan as a South Asian country that shares borders with India and is part of the Indian subcontinent.Step 4: Recognize that America, meaning the United States of America, is a country in North America, not in South Asia.Step 5: Since India, Bangladesh and Pakistan are all part of the Indian subcontinent and America is not, America is the odd one out.Verification / Alternative check:You can verify by recalling typical groupings: India, Pakistan and Bangladesh often appear together in discussions about South Asia, regional conflicts, shared history and culture. The United States is geographically far away and part of a different continent. Therefore, region wise classification clearly isolates America as the unique option among the four.Why Other Options Are Wrong:India is not the odd one out because it is firmly located in the Indian subcontinent and shares historical and cultural ties with Bangladesh and Pakistan. Bangladesh is not the odd one out as it is also a South Asian country in the Indian subcontinent, with close geographical and historical links to India and Pakistan. Pakistan is likewise a South Asian country in the Indian subcontinent, so it belongs in the same regional category as India and Bangladesh. Common Pitfalls:Some learners may misinterpret the term America to mean the continents of North and South America, but in common usage in such questions it usually refers to the United States of America. Another pitfall is to focus on economic or political alliances rather than geographic region. The most robust and exam oriented way to group these countries is by continent and subcontinent, which makes the correct answer straightforward.Final Answer:The only country that does not belong to the Indian subcontinent is America, so America is the odd one out.

Question 9

In this personality and achievement based odd one out question, select the name that does not belong to the group of Indian scientists and science related achievers among Bismillah Khan, C. V. Raman, Homi Jehangir Bhabha and Vikram Sarabhai.

Accepted Answer

Introduction / Context:This general knowledge odd one out question tests your awareness of famous Indian personalities and their fields of contribution. Three of the names belong to well known scientists or science related achievers, while one is a celebrated musician. Recognizing the domain of each person is essential to answering the question correctly.Given Data / Assumptions: The given names are Bismillah Khan, C. V. Raman, Homi Jehangir Bhabha and Vikram Sarabhai. We assume standard historical and biographical knowledge of these personalities. The classification of each person by primary field of contribution is the key. Concept / Approach:The approach is to recall the main area in which each person is famous. C. V. Raman, Homi Jehangir Bhabha and Vikram Sarabhai are all closely associated with science, especially physics, nuclear research and space research in India. Bismillah Khan, on the other hand, is known for his contribution to Indian classical music, particularly the shehnai. Therefore, Bismillah Khan is the odd one out by field of work.Step-by-Step Solution:Step 1: C. V. Raman was a renowned Indian physicist who received the Nobel Prize in Physics for the Raman effect.Step 2: Homi Jehangir Bhabha was a pioneering Indian nuclear physicist, often regarded as the father of the Indian nuclear program.Step 3: Vikram Sarabhai was an eminent Indian scientist and is widely recognized as the father of the Indian space program.Step 4: Bismillah Khan was a legendary Indian classical musician, famous for popularizing the shehnai and contributing greatly to Indian music, not to science.Step 5: Since C. V. Raman, Homi Jehangir Bhabha and Vikram Sarabhai are all known for their scientific contributions, while Bismillah Khan is known for his contribution to music, Bismillah Khan is the odd one out.Verification / Alternative check:You can verify this grouping by recalling the institutions and awards associated with each person. Research centers, scientific awards and space missions frequently mention Raman, Bhabha and Sarabhai. Bismillah Khan, however, is referenced in the context of concerts, music awards and cultural events. This confirms that his domain is music, not science.Why Other Options Are Wrong:C. V. Raman is not the odd one out because he is a scientist and belongs with Bhabha and Sarabhai in the science group. Homi Jehangir Bhabha is also firmly in the scientist category, making him part of the majority group. Vikram Sarabhai is another noted scientist and architect of the Indian space program, so he is clearly not unique here. Common Pitfalls:A candidate who is not familiar with Indian personalities might try to guess based on name familiarity. Another mistake is confusing fields, for example mistakenly thinking that one of the scientists belongs to a different domain. To improve accuracy, aspirants should regularly review important Indian personalities and categorize them by domain such as politics, science, sports and arts.Final Answer:The only personality who is a musician rather than a scientist is Bismillah Khan, so Bismillah Khan is the odd one out.

Question 10

In this alphabet pair odd one out question, choose the pair of letters that does not follow the pattern of moving backwards by four positions in the alphabet among VR, LH, SW and FB.

Accepted Answer

Introduction / Context:This is a verbal reasoning question based on letter pairs. You need to determine which pair of letters does not follow the same movement rule in the alphabet as the others. These types of questions train candidates to recognize positional relationships between letters quickly.Given Data / Assumptions: The letter pairs are VR, LH, SW and FB. We use A to Z as positions 1 to 26. The suspected pattern involves shifting a fixed number of positions forward or backward in the alphabet. Concept / Approach:First, convert each letter into its alphabetical position and then compute the difference between the first and second letters in each pair. If three pairs show the same difference and direction, while one does not, that anomalous pair is the odd one out. Here, most pairs move four positions backward, while one pair moves forward.Step-by-Step Solution:Step 1: For VR, V is the 22nd letter and R is the 18th letter. Difference = 18 - 22 = -4, which is 4 positions backward.Step 2: For LH, L is the 12th letter and H is the 8th letter. Difference = 8 - 12 = -4, again 4 positions backward.Step 3: For FB, F is the 6th letter and B is the 2nd letter. Difference = 2 - 6 = -4, so this pair also moves 4 positions backward.Step 4: For SW, S is the 19th letter and W is the 23rd letter. Difference = 23 - 19 = +4, which means 4 positions forward, not backward.Step 5: Since VR, LH and FB each show a backward movement of 4 positions, while SW shows a forward movement of 4 positions, SW breaks the pattern and is the odd one out.Verification / Alternative check:You can mentally count letters: from V backwards four steps is U, T, S, R; from L backwards four steps is K, J, I, H; from F backwards four steps is E, D, C, B. In contrast, from S forwards four steps is T, U, V, W. This quick check confirms that SW is the only pair moving forward in the alphabet, reinforcing the conclusion.Why Other Options Are Wrong:VR is not the odd one out because it clearly follows the rule of moving four positions backward from the first letter to the second letter. LH also fits the same backward step of 4 positions and thus belongs with VR and FB. FB consistently applies the same backward shift of 4 positions, which is the central pattern in this question. Common Pitfalls:A common error is to ignore direction and only count the absolute difference between positions, overlooking whether the movement is forward or backward. Another mistake is miscounting the number of steps between letters, especially when working mentally under time pressure. To avoid confusion, always pay attention to whether the second letter comes before or after the first letter in the alphabet.Final Answer:The only pair that moves four positions forward instead of backward is SW, so SW is the odd one out.

Question 11

In this digit sum based odd one out question, you must choose the three digit number whose digit sum is different from the common digit sum of the other numbers among 863, 785, 791 and 647.

Accepted Answer

Introduction / Context:This is a simple yet effective digit sum odd one out question in the number system category. The task is to determine which number has a different total of digits compared to the others. Digit sum patterns commonly appear in reasoning tests because they are quick to compute and highlight hidden relationships among numbers.Given Data / Assumptions: The numbers are 863, 785, 791 and 647. We work with the base 10 representation of each number and use each of the three digits. The suspected pattern involves the sum of digits. Concept / Approach:The idea is to calculate the sum of the digits of each number and look for a common value. If three numbers share the same digit sum and one number has a different sum, the number with the different sum is the odd one out. This approach is straightforward and does not require deep numerical theory.Step-by-Step Solution:Step 1: For 863, digits are 8, 6 and 3. Sum = 8 + 6 + 3 = 17.Step 2: For 785, digits are 7, 8 and 5. Sum = 7 + 8 + 5 = 20.Step 3: For 791, digits are 7, 9 and 1. Sum = 7 + 9 + 1 = 17.Step 4: For 647, digits are 6, 4 and 7. Sum = 6 + 4 + 7 = 17.Step 5: We observe that 863, 791 and 647 each have a digit sum of 17, while 785 has a digit sum of 20. Therefore, 785 is the odd one out.Verification / Alternative check:You can recheck by adding the digits again or by grouping them differently, such as (8 + 6) + 3 for 863 and so on. The consistency of the repeated sum of 17 for three numbers and the different result of 20 for 785 confirms that 785 is unique in terms of digit sum, which is the intended pattern in this question.Why Other Options Are Wrong:863 is not the odd one out because its digit sum of 17 matches that of 791 and 647. 791 is also not unique since its digit sum is 17, the same as 863 and 647. 647 similarly has a digit sum of 17, aligning it with 863 and 791. Common Pitfalls:Students may attempt to look for more complex patterns like prime numbers or factorization and overlook the simple digit sum relation. Another common issue is careless addition, which might lead to an incorrect sum and hence a wrong choice. Being systematic and double checking simple calculations can prevent such mistakes and is a valuable habit in all numerical reasoning questions.Final Answer:The only three digit number with a different digit sum is 785, so 785 is the odd one out.

Question 12

In this number pattern odd one out question, identify the four digit number whose digit sum is even while the digit sums of the other numbers are odd among 3284, 4058, 2137 and 2363.

Accepted Answer

Introduction / Context:This question is a number pattern odd one out based on the parity of the sum of digits. You are given four four digit numbers and must choose the one whose digit sum does not share the same parity (odd or even) as the others. Such problems help build attention to detail and comfort with quick mental arithmetic.Given Data / Assumptions: The numbers are 3284, 4058, 2137 and 2363. Each number is considered in its base 10 digit form. The pattern involves checking whether the sum of digits is odd or even. Concept / Approach:The key idea is to compute the sum of the digits of each number and then observe whether the result is odd or even. If three numbers have an odd digit sum and one number has an even digit sum, the one with a different parity is the odd one out. This method relies on simple addition and parity recognition.Step-by-Step Solution:Step 1: For 3284, digits are 3, 2, 8 and 4. Sum = 3 + 2 + 8 + 4 = 17, which is odd.Step 2: For 4058, digits are 4, 0, 5 and 8. Sum = 4 + 0 + 5 + 8 = 17, which is odd.Step 3: For 2137, digits are 2, 1, 3 and 7. Sum = 2 + 1 + 3 + 7 = 13, which is odd.Step 4: For 2363, digits are 2, 3, 6 and 3. Sum = 2 + 3 + 6 + 3 = 14, which is even.Step 5: Since 3284, 4058 and 2137 all have odd digit sums, while 2363 has an even digit sum, 2363 is the odd one out.Verification / Alternative check:To verify, you can quickly double check the sums: 3 + 2 + 8 + 4 = 17, 4 + 0 + 5 + 8 = 17, 2 + 1 + 3 + 7 = 13 and 2 + 3 + 6 + 3 = 14. The parity pattern odd, odd, odd, even is clear. No further advanced check is necessary, making this a straightforward odd one out problem.Why Other Options Are Wrong:3284 is not the odd one out because its digit sum is 17, which is odd, matching 4058 and 2137. 4058 also has an odd digit sum of 17 and therefore aligns with 3284 and 2137. 2137 has an odd digit sum of 13, which again places it in the same parity group as 3284 and 4058. Common Pitfalls:If a candidate rushes, they might miscalculate a sum, especially in multi digit numbers, leading to an incorrect classification of parity. Another mistake is to search for more complex properties such as divisibility by specific numbers or prime status, which is unnecessary here. Practicing digit sum computations improves speed and accuracy in a broad range of numerical reasoning questions.Final Answer:The only number with an even digit sum is 2363, so 2363 is the odd one out.

Question 13

In this alphabet sequence odd one out question, select the letter triplet that does not follow the +1 and +2 forward movement rule in the alphabet among LMO, PQS, XYB and DEG.

Accepted Answer

Introduction / Context:This problem is an alphabet sequence odd one out question. The focus is on identifying which of the given three letter sequences does not follow a common pattern of incremental steps in the alphabet. Such questions sharpen a candidate understanding of the alphabet as a numerical sequence and their ability to detect regular jumps between letters.Given Data / Assumptions: The letter triplets are LMO, PQS, XYB and DEG. We use alphabetical positions: A = 1, B = 2, ..., Z = 26. The pattern to check involves differences between consecutive letters. Concept / Approach:The approach is to convert each letter to its numerical position and compute the difference between the first and second letter, and between the second and third letter. If three triplets follow a consistent pattern of +1 and +2, while one triplet does not, the non conforming triplet is the odd one out.Step-by-Step Solution:Step 1: For LMO, L is 12, M is 13 and O is 15. Differences are 13 - 12 = 1 and 15 - 13 = 2.Step 2: For PQS, P is 16, Q is 17 and S is 19. Differences are 17 - 16 = 1 and 19 - 17 = 2.Step 3: For DEG, D is 4, E is 5 and G is 7. Differences are 5 - 4 = 1 and 7 - 5 = 2.Step 4: For XYB, X is 24, Y is 25 and B is 2. Differences if we move forward in the alphabet are 25 - 24 = 1 and 2 - 25, which does not equal 2 and also implies wrapping around the alphabet, breaking the simple +1 and +2 pattern.Step 5: Since LMO, PQS and DEG all follow the pattern first difference = +1 and second difference = +2, while XYB does not, XYB is the odd one out.Verification / Alternative check:You can think of each correct sequence as stepping to the very next letter and then skipping one letter. For example, L to M is immediate next and M to O skips N. Exactly the same style holds for PQS and DEG. XYB, however, would require wrap around from Y to B and does not produce a simple two step forward movement, so it clearly does not fit the same model.Why Other Options Are Wrong:LMO is not the odd one out because it follows the consistent +1, +2 pattern. PQS also conforms exactly to the +1, +2 sequence rule in the alphabet. DEG similarly follows the same pattern and therefore belongs with LMO and PQS. Common Pitfalls:Some learners may try to treat the alphabet as circular and attempt to justify XYB with complicated wrap around logic. However, in most exam questions the simplest forward pattern is intended. Another issue is confusing letter positions, especially towards the end of the alphabet. Regular practice with mapping letters to numbers can prevent such errors.Final Answer:The only triplet that does not follow the pattern of +1, then +2 in the alphabet is XYB, so XYB is the odd one out.

Question 14

In this perfect power based odd one out question, select the number that is a perfect cube while the others are perfect squares among 256, 289, 343 and 144.

Accepted Answer

Introduction / Context:This question belongs to the number system category and focuses on perfect squares and perfect cubes. You must identify the number that is a perfect cube while the rest are perfect squares. Recognizing common squares and cubes of small integers is an essential skill for many competitive examinations.Given Data / Assumptions: The given numbers are 256, 289, 343 and 144. We consider perfect squares n^2 and perfect cubes n^3 for integer values of n. The pattern contrasts square numbers against a cube number. Concept / Approach:The idea is to factor each number or recall standard squares and cubes from memory. If three numbers are perfect squares and one number is a perfect cube but not a perfect square, that cube is the odd one out. Knowledge of squares up to at least 20 and cubes up to at least 10 is very useful here.Step-by-Step Solution:Step 1: 256 can be recognized as 16^2, so it is a perfect square.Step 2: 289 is equal to 17^2, so it is also a perfect square.Step 3: 144 is equal to 12^2, which again makes it a perfect square.Step 4: 343 is equal to 7^3. It is not equal to any integer squared value, so it is a perfect cube but not a perfect square.Step 5: Since 256, 289 and 144 are perfect squares and 343 is a perfect cube, 343 does not share the same property and is therefore the odd one out.Verification / Alternative check:You can verify by checking nearby squares and cubes. For example, 6^3 = 216, 7^3 = 343 and 8^3 = 512, which confirms that 343 is a cube. Attempting to find an integer n such that n^2 = 343 fails, since 18^2 = 324 and 19^2 = 361. Therefore, 343 is indeed a cube but not a square, whereas the others are confirmed squares.Why Other Options Are Wrong:256 is not the odd one out because it is a perfect square and so matches 289 and 144. 289 is also a perfect square and thus part of the majority group of square numbers. 144 is yet another perfect square, aligning with 256 and 289 and not unique in its property. Common Pitfalls:Some candidates might think of 256 as special because it is also 2^8, which is a higher power, but that is not the intended comparison. The question clearly focuses on whether numbers are squares or cubes. Another mistake is to forget or misremember key squares and cubes. Regular revision of a table of squares and cubes up to at least 20 helps avoid such errors.Final Answer:The only number that is a perfect cube while the others are perfect squares is 343, so 343 is the odd one out.

Question 15

In this sports terminology odd one out question, choose the term that is mainly associated with another sport while the others belong to cricket among Duckworth-Lewis method, Googly, Dribbling and Leg before wicket.

Accepted Answer

Introduction / Context:This question belongs to the general knowledge and sports terminology category. You must identify which term is not primarily associated with the game of cricket. Three of the terms are directly related to cricket, while one is commonly used in sports like football and basketball. Recognizing sports specific vocabulary is useful in many competitive exams.Given Data / Assumptions: The terms are Duckworth-Lewis method, Googly, Dribbling and Leg before wicket. We assume standard usage of these words in sports contexts. The grouping is based on the sport in which the term is generally used. Concept / Approach:The approach is to recall what each term means and in which sport it is used. Duckworth-Lewis method is a mathematical formula used in cricket to adjust targets in rain affected matches. Googly is a type of delivery by a spin bowler in cricket. Leg before wicket, often abbreviated as LBW, is a mode of dismissal in cricket. Dribbling, however, is a skill mainly associated with controlling the ball in football or basketball, not with cricket. Therefore, Dribbling is the odd one out.Step-by-Step Solution:Step 1: Duckworth-Lewis method is a rule in limited overs cricket used to calculate revised targets when play is interrupted by weather.Step 2: Googly is a deceptive leg spin bowling delivery in cricket that turns in the opposite direction to a normal leg break.Step 3: Leg before wicket is a mode of dismissal in cricket where the batsman can be declared out if the ball strikes the body, usually the leg, in line with the stumps under certain conditions.Step 4: Dribbling refers to repeatedly tapping, pushing or bouncing the ball with the feet in football or with the hands in basketball, to move forward while maintaining control.Step 5: Since Duckworth-Lewis method, Googly and Leg before wicket are all associated specifically with cricket, while Dribbling belongs mainly to football and basketball, Dribbling is the odd one out.Verification / Alternative check:You can cross check by thinking of where you commonly hear each term. Cricket commentary and rule books frequently mention Duckworth-Lewis method, Googly and LBW decisions. In contrast, Dribbling is a fundamental concept in football coaching and basketball training and is rarely or never used in orthodox cricket terminology, which verifies the classification.Why Other Options Are Wrong:Duckworth-Lewis method is not the odd one out because it is a cricket specific rule. Googly is not the odd one out since it is clearly a cricket bowling term. Leg before wicket also firmly belongs to cricket as a mode of dismissal, matching the context of Duckworth-Lewis and Googly. Common Pitfalls:Some learners may overthink and consider cricket to be a ball based game like football and thus misclassify Dribbling as loosely related. However, the question is about standard technical terminology, not generic ball movement. Another mistake is incomplete familiarity with cricket rules, so revising major cricket terms can be very helpful for such questions.Final Answer:The only term that is not primarily a cricket term is Dribbling, so Dribbling is the odd one out.

Question 16

In this letter sequence odd one out question, choose the six letter group that does not end with three letters in strictly descending order among IJKRQP, FGHUTS, BCDWXY and KLMPON.

Accepted Answer

Introduction / Context:This is a letter sequence odd one out question that focuses on patterns within six letter groups. Each group has three letters in the beginning and three letters at the end. The aim is to identify which sequence does not share the same pattern of the last three letters being in strictly descending alphabetical order.Given Data / Assumptions: The letter groups are IJKRQP, FGHUTS, BCDWXY and KLMPON. We use standard alphabetical positions from A to Z. The pattern primarily concerns the order of the last three letters in each sequence. Concept / Approach:The idea is to separate each six letter group into the first three letters and the last three letters. On inspection, three of the groups end with three letters in descending order, while one group ends with three letters in ascending order. The group that does not follow the descending order pattern is the odd one out.Step-by-Step Solution:Step 1: For IJKRQP: the last three letters are R, Q and P. In the alphabet, R comes before Q and Q comes before P, so they are in descending order.Step 2: For FGHUTS: the last three letters are U, T and S. U comes before T and T comes before S, again forming a descending sequence.Step 3: For KLMPON: the last three letters are P, O and N. P comes before O and O comes before N, so they also form a descending sequence.Step 4: For BCDWXY: the last three letters are W, X and Y. Here, W comes before X and X comes before Y, which is an ascending sequence, not descending.Step 5: Since the last three letters in IJKRQP, FGHUTS and KLMPON are in descending order, while BCDWXY ends in ascending order, BCDWXY is the odd one out.Verification / Alternative check:You can double check by writing the last three letters of each group separately and comparing them: RQ P, U T S, P O N are backwards runs, whereas W X Y is a forward run in the alphabet. This direct comparison makes it clear that only BCDWXY does not share the pattern of descending order in the final trio of letters.Why Other Options Are Wrong:IJKRQP is not the odd one out because RQ P is in strict descending alphabetical order. FGHUTS is not the odd one out since U T S is also a descending sequence. KLMPON likewise ends with P O N, which again is in descending order, aligning it with the previous two. Common Pitfalls:Some candidates may focus on the first three letters instead of the last three or try to find more complicated patterns in the entire six letter sequence. While such patterns may exist, the simplest and most consistent feature here is the ordering of the last three letters. Always start with the most obvious and consistent pattern, especially when dealing with exam questions under time constraints.Final Answer:The only sequence whose last three letters are in ascending, not descending order, is BCDWXY, so BCDWXY is the odd one out.

Question 17

In this digit arrangement odd one out question, select the five digit number that forms a strictly descending sequence of digits among 67559, 45189, 56341 and 54321.

Accepted Answer

Introduction / Context:This is a digit arrangement odd one out question. You are given four five digit numbers and must identify which one has all digits in strictly descending order, while the others do not. Such questions test pattern recognition and visual observation skills in the context of number sequences.Given Data / Assumptions: The numbers are 67559, 45189, 56341 and 54321. We examine the order of digits from left to right. The pattern relates to whether the digits form a strictly descending series. Concept / Approach:The approach is to check for monotonic order of digits. Strictly descending order means each digit must be smaller than the digit before it, with no equal digits and no reversals. If only one number satisfies this property, that number is the odd one out in terms of pattern, even though in context it appears special or unique compared to the others.Step-by-Step Solution:Step 1: For 67559, the digits are 6, 7, 5, 5 and 9. The order is not strictly descending, since 7 is greater than 6 and there are equal digits 5, 5 and then an increase to 9.Step 2: For 45189, the digits are 4, 5, 1, 8 and 9. The sequence goes up from 4 to 5, down to 1, up to 8 and up again to 9, so there is no simple descending order.Step 3: For 56341, the digits are 5, 6, 3, 4 and 1. The pattern oscillates and does not move in one consistent descending direction.Step 4: For 54321, the digits are 5, 4, 3, 2 and 1. Each digit is exactly one less than the previous digit, so the sequence is strictly descending.Step 5: Since only 54321 has digits in perfect descending order, it is the odd one out when compared to the other three, which have mixed or irregular digit patterns.Verification / Alternative check:A quick visual scan confirms that 54321 reads as a neat countdown from 5 to 1, something the other numbers do not replicate. You can also count differences: for 54321, every step is a -1 change. No other number shows such a simple and consistent pattern, confirming 54321 as the unique case.Why Other Options Are Wrong:67559 is not the odd one out because its digits are neither strictly increasing nor strictly decreasing, and the pattern is irregular. 45189 also has a mixed pattern with rises and falls, making it similar in irregularity to 67559 and 56341. 56341 again shows no strict descending order, so it belongs with the irregular patterns rather than standing apart. Common Pitfalls:Some learners might incorrectly think of the odd one out as any number with repeated digits or a particular digit combination. However, the key is to focus on the order of digits. Another pitfall is scanning too quickly and missing subtle changes in direction. Slow, methodical checking of each transition between digits helps avoid such errors.Final Answer:The only number whose digits are arranged in a strictly descending sequence is 54321, so 54321 is the odd one out.

Question 18

In this everyday object odd one out question, you must choose the item that is not a piece of furniture used for seating or support in a living room among Armchair, Sofa, Table and Paperweight.

Accepted Answer

Introduction / Context:This question is a simple general knowledge and vocabulary based odd one out problem. It asks you to identify which item among the four options is not a typical piece of furniture or large household item commonly used in a living room. Recognizing categories of everyday objects is a basic yet important reasoning skill.Given Data / Assumptions: The items listed are Armchair, Sofa, Table and Paperweight. We assume the context of common household furniture and accessories. The standard usage of each item is considered. Concept / Approach:Armchair, Sofa and Table are all pieces of furniture. They are relatively large objects used for sitting or placing things and form core parts of room furnishings. A Paperweight, however, is a small object used to hold down papers on a desk and is not furniture. Therefore, the item that does not belong to the category of furniture is the odd one out.Step-by-Step Solution:Step 1: Armchair is a piece of furniture designed for one person to sit comfortably, often with arms and cushioning.Step 2: Sofa is a larger piece of seating furniture, designed to allow several people to sit together, commonly placed in living rooms.Step 3: Table is a piece of furniture with a flat top and legs, used to place items, eat meals or work.Step 4: Paperweight is a small, often decorative object placed on top of papers to prevent them from blowing away. It is an accessory, not furniture.Step 5: Since Armchair, Sofa and Table are all pieces of furniture, while Paperweight is a small desk accessory, Paperweight is the odd one out.Verification / Alternative check:You can verify by considering size and function. Furniture items are usually large, central objects in a room, needed for seating or work surfaces. A Paperweight is a small supplementary object used on top of a table or desk. Therefore, functionally and categorically, Paperweight does not belong with the other three items.Why Other Options Are Wrong:Armchair is not the odd one out because it is clearly furniture for sitting, like Sofa and related to Table as a major room item. Sofa is also a primary seating furniture item and clearly belongs with Armchair as a core furnishing. Table is a standard piece of furniture providing a surface and is not unique in category compared to Armchair and Sofa. Common Pitfalls:Sometimes candidates overthink and attempt to classify based on room type, such as assuming a Table might be in a dining room rather than a living room. However, tables exist in many rooms and remain furniture. The simplest and correct classification is that Paperweight is not furniture at all, whereas the others are. Keeping the categorization broad and functional avoids confusion.Final Answer:The only item that is not a piece of furniture is Paperweight, so Paperweight is the odd one out.

Question 19

In this alphabet pattern odd one out question, select the letter triplet that does not follow the pattern of +6 then -3 in alphabetical positions among JPM, DJG, BHE and SDA.

Accepted Answer

Introduction / Context:This is an alphabet pattern odd one out question. Each option is a group of three letters and the rule relates to the jumps in the alphabet between these letters. Three of the groups follow a pattern of moving six steps forward and then three steps backward in the alphabet, while one group does not follow this pattern.Given Data / Assumptions: The letter triplets are JPM, DJG, BHE and SDA. We use standard alphabetical positions from 1 to 26. The pattern involves shifts between the first, second and third letter in each triplet. Concept / Approach:The strategy is to convert each letter to its numerical position and then compute the difference between consecutive letters. For three of the triplets, the first to second letter change is +6 and the second to third letter change is -3. The triplet that does not show this pattern is the odd one out.Step-by-Step Solution:Step 1: For JPM: J is 10, P is 16 and M is 13. Differences are 16 - 10 = +6 and 13 - 16 = -3.Step 2: For DJG: D is 4, J is 10 and G is 7. Differences are 10 - 4 = +6 and 7 - 10 = -3.Step 3: For BHE: B is 2, H is 8 and E is 5. Differences are 8 - 2 = +6 and 5 - 8 = -3.Step 4: For SDA: S is 19, D is 4 and A is 1. Differences are 4 - 19 = -15 and 1 - 4 = -3. This does not match the +6, -3 pattern.Step 5: Since JPM, DJG and BHE each show a +6 then -3 shift, while SDA does not, SDA is the odd one out.Verification / Alternative check:You can also verify by counting manually: for example, starting from J, count six letters forward to reach P and then three letters backward to reach M. The same pattern appears in DJG and BHE, but SDA breaks the pattern immediately since the first change is backward by 15 letters. This confirms that SDA is not consistent with the others.Why Other Options Are Wrong:JPM follows the +6, -3 alphabetical stepping pattern and therefore belongs with DJG and BHE. DJG also matches the same pattern and is not unique. BHE fits the same rule, clearly aligning with JPM and DJG in structure. Common Pitfalls:One common mistake is ignoring the sign of the difference and focusing only on the absolute value, which could obscure the fact that SDA has the wrong direction in its first step. Another pitfall is miscounting letters when moving forward or backward. Consistent practice with letter position mapping helps reduce such errors.Final Answer:The only letter triplet that does not follow the +6, then -3 pattern is SDA, so SDA is the odd one out.

Question 20

In this divisibility based odd one out question, select the number that is not divisible by 4 among 156, 200, 182 and 240.

Accepted Answer

Introduction / Context:This question tests divisibility skills in the number system segment. You must determine which of the four given numbers is not a multiple of 4. Divisibility by 4 is a basic concept frequently used in aptitude exams, and knowing the rule allows quick elimination of options.Given Data / Assumptions: The numbers are 156, 200, 182 and 240. We assume the standard divisibility rule for 4: a number is divisible by 4 if the last two digits form a number divisible by 4. The odd one out will be the only number that fails this divisibility test. Concept / Approach:The key rule is that for any integer, if the number formed by its last two digits is divisible by 4, then the whole number is divisible by 4. Instead of dividing each number entirely, we only need to check the last two digits. By applying this rule, we can quickly find which number is not divisible by 4.Step-by-Step Solution:Step 1: For 156, look at the last two digits, 56. 56 / 4 = 14, an integer, so 156 is divisible by 4.Step 2: For 200, the last two digits are 00. 0 is divisible by 4, so 200 is divisible by 4.Step 3: For 240, the last two digits are 40. 40 / 4 = 10, an integer, so 240 is divisible by 4.Step 4: For 182, the last two digits are 82. 82 / 4 = 20.5, which is not an integer, so 182 is not divisible by 4.Step 5: Since 156, 200 and 240 are divisible by 4 and 182 is not, 182 is the odd one out.Verification / Alternative check:As an alternative check, you can perform direct division: 156 / 4 = 39, 200 / 4 = 50 and 240 / 4 = 60, all integers. For 182 / 4, you obtain 45.5, which is not an integer, confirming that 182 is not a multiple of 4. This reinforces the result obtained using the last two digits rule.Why Other Options Are Wrong:156 is not the odd one out as it is clearly divisible by 4 according to the rule. 200 is also divisible by 4 and therefore belongs with 156 and 240. 240 is divisible by 4 and fits the same pattern as 156 and 200. Common Pitfalls:A common mistake is to check only whether a number is even and assume that every even number is divisible by 4. This is incorrect, because many even numbers like 182 are not multiples of 4. Another error is to perform full division under time pressure and make arithmetic mistakes. Using the last two digits rule is both faster and more reliable in exam situations.Final Answer:The only number that is not divisible by 4 is 182, so 182 is the odd one out.

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