Four persons are to be choosen from a group of 3 men, 2 women and 4 children. Find the probability of selecting 1 man,1 woman and 2 children.

Total number of persons = 9

Out of 9 persons 4 persons can be selected in $9C4$ ways =126

1 man,1 woman and 2 children can be selected in $3C1*2C1*4C1$ ways =36
So,required probability = 36/126 =2/7