Two unbiased dice are thrown simultaneously. the probability of getting the sum divisible by 3, is?

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Accepted Answer

n(S) = 6 x 6 = 36 n(E) = (1, 2) (2, 1), (1, 5) (2, 4) (3, 3) (4, 2) (5, 1) (3, 6) (4, 5) (5, 4) (6, 3) (6, 6) = 12 ∴ P(E) = 12/36

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