What is the possibility of getting at least 6 heads, if eight coins are tossed simultaneously?

Required probability = Probability of getting 2 tails + Probability of getting 1 tail + Probability of getting no tail.
= ⁸C₂ x 1/256 + ⁸C₁ x 1/256 + ⁸C₀ x 1/256
= 37/256