Question 1

Laxman has to cover a distance of 6 km in 45 minutes . If he cover one half of the distance in 2/3 rd time . what should be his speed to cover the remaining distance in the remaining time?

Accepted Answer

∵ Time left = (1/3 X 45/60) hr. = 1/4 hr. Distance left = 3km ∴ speed required = [3 / (1/4) ] km/hr. = 3 x 4 =12km/hr .

Question 2

A train cover a distance in 50 minutes, if it runs at a speed of 48 km per hour on an average. The speed at which the train must run to reduce the time of journey to 40 minutes?

Accepted Answer

Total Distance = 48 x (50/60) km. = 40 km Required speed = [40 / (40/60)] km. = (40 x 60 )/ 40 km/hr. = 60 km/hr.

Question 3

Excluding stoppages, the speed of a bus is 54 km/hr. and including stoppages it is 45 km/hr. for how many minutes does the bus stop per hour?

Accepted Answer

Due to stoppages, it covers 9 km. less per hour Required time = Time taken to cover 9 km. = 9 / ( 54 /60) min = 10 min

Question 4

Two men start together to walk to a certain destination, one at 3.75 km an hour and another at 3 km an hour. The former arrives half an hour before the latter, the distance is?

Accepted Answer

Let the distance be y km. From question y/3 - y/3.75 = 1/2 ⇒ (3.75y - 3y) / (3 x 3.75) = 1/2 ⇒ 1.5y= 3 x 3.75 ∴ y = ( 3 x 3.75 ) / 1.5 = 7.5 km.

Question 5

A car covers four successive three km stretches at speed of 10 km/hr, 20 km/hr, 30 km/hr and 60 km/hr. respectively. Its average speed over this distance is?

Accepted Answer

Total time taken = (3/10 + 3/20 + 3/30 + 3/60) hrs. = 3/5 hrs. ∴ Average speed = {12 / (3 / 5)} km/hr. = (12 x 5 ) / 3 km/hr. = 20 km/hr.

Question 6

A car complete a certain journey in 8 hour. It cover half the distance at 40 km/hr and the rest at 60 km/hr, The length of a journey is?

Accepted Answer

Let the length of total journey be y km. From question ( y/2 x 1/40 ) + ( y/2 x 1/60) = 8 ⇒ y/80 + y/120 = 8 ⇒ 3y + 2y = 1920 ∴ y = 384 km.

Question 7

Rahim covers a certain distance in 14 hrs 40 min. He covers one half of the distance by train at 60 km/hr. and rest half by road at 50 km/hr. The distance travelled by him is?

Accepted Answer

Let the total distance be y km. Then, (y/2) x (1/60) + (y/2) x (1/50) = 44/3 ⇒ y/120 + y/100 = 44/3 ⇒ 5y + 6y = 8800 ⇒ y = 800 ∴ Required distance = 800km.

Question 8

A man perform 2/15 of the total journey by rail, 9/20 by tonga and the remaining 10 km on foot. This total journey is?

Accepted Answer

Let the total journey be x km. then, 2x/15 + 9x/20 + 10 = x ⇒ 8x + 27x + 600 = 60x ⇒ x = 24 ∴ Total journey = 24 km.

Question 9

Shard cover two-third of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is?

Accepted Answer

Let total distance be y km. Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60 ⇒ y/6 + y/ 15 = 7/10 ⇒ 5y + 2y = 21 ∴ y = 3 ∴ Required distance = 3 km.

Question 10

A boy goes to school with a speed of 3 km/hr. and return to the village with a speed of 2 km/hr. If he takes 5 hours in all, then distance between the village and the school is?

Accepted Answer

Let The required distance be y km. Then, y/3 + y/2 = 5 ⇒ 2y + 3y = 30 ⇒ y = 6 km

Question 11

A distance is covered in 2 hours 45 min at 4 km/hr How much time will be taken to cover it at 16.5 km/hr?

Accepted Answer

Distance = (4 x 11/4 )km. = 11 km. ∴ Req. Time = 11km / (33/2) km/hr = 2 x (11 / 33) hr. =(2 / 3) x 60 minutes = 40 minutes

Question 12

If a man takes 4 hours to cover a distance of 15 km. how much time will be needed to cover 63 km. at the same speed?

Accepted Answer

Required time = (4 / 15) x 63 hrs. = 16 hrs. 48 min

Question 13

A train is moving with a speed of 92.4 km/hr. how many meters will it cover in 10 min.?

Accepted Answer

Speed in m/sec = ( 5 / 18 ) x Speed in kms/hr. 92.4 kms/hr = 92.4 x (5 / 18) m/sec. ∴ Req. distance = 92.4 x ( 5 / 18 ) x 600 meters = 15400 m.

Question 14

if a man cover 10.2 km. in 3 hours. The distance covered by him in 5 hours is?

Accepted Answer

Speed = 10.2 / 3 km/hr. = 3.4 km/hr. Distance covered in 5 hours = 3.4 X 5 km. = 17 km

Question 15

A man crosses a streets 600 m long in 5 minutes. His speed in km per hour is?

Accepted Answer

Speed = 600 / (5 x 60) m/sec. = 600 / (5 x 60) x 18/5 km/hr. = 7.2 km/hr.

Question 16

A and B are two towns. Mr. Faruqui covers the distance from A to B on cycle at 16 km/hr. however, he cover the distance from B to A on foot at 9 km/hr. his average speed during the whole journey is?

Accepted Answer

Average Speed = Total distance / time = 2d / [( d / 16) + ( d / 9)] = ( 2 x 16 x 9 ) / ( 16 + 9 ). = 11.52 km/hr. Shortcut : Average speed = 2uv / (u + v) = ( 2 x 16 x 9 ) / ( 16 + 9 ) = 11.52

Question 17

A speed of 22.5 m/sec. is the same as?

Accepted Answer

Speed in km/hr = speed in m/sec x (18 / 5 ) Speed in km/hr = (22.5 x 18 /5 ) km/hr = 81 km/hr.

Question 18

A speed of 55 m / sec. is the same as?

Accepted Answer

Speed in km/hr = speed in m/sec x (18 / 5 ) Speed in km/hr = ( 55 x 18 /5 ) km/hr = 198 km/hr.

Question 19

A speed of 30.6 km/hr. is the same as?

Accepted Answer

Speed in m/sec = speed in km/hr x (5 / 18 ) Speed in m/sec = ( 30.6 x 18 /5 ) m/sec = 8.5 m/sec

Question 20

A speed of 36 km/hr. is the same as?

Accepted Answer

Speed in m/sec = speed in km/hr x (5 / 18 ) Speed in m/sec = ( 36 x 5/18 ) m/sec = 10 m/sec

Time and Distance Questions