Question 1

Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ?

Accepted Answer

Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms

Question 2

A train covers 180 km distance in 5 hours. Another train covers the same distance in 1 hour less. What is the difference in the distances covered by these trains in one hour if they are moving in the same direction?

Accepted Answer

The first train covers 180 kms in 5 hrs => Speed = 180/5 = 36 kmph Now the second train covers the same distance in 1 hour less than the first train => 4 hrs => Speed of the second train = 180/4 = 45 kmph Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.

Question 3

A goods truck travels from a place at a certain time and at fixed speed. After 6hrs another truck leaves the same place and move in same direction of uniform speed of 90kmph. The truck catches up the goods truck in 4hrs. Find the speed of the goods …

Accepted Answer

Let the speed of goods truck be 'p' kmph Distance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs. 10p = 4 x 90 p = 36kmph. Therefore, the speed of the goods truck is p = 36 kmph.

Question 4

A thief goes away with a MARUTHI car at a speed of 40 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 50 kmph when will the owner over take the thief from the start ?

Accepted Answer

|-----------20--------------------| 50 40 Difference = 20kms Relative Speed = 50 – 40 = 10 kmph Time = 20/10 = 2 hours.

Question 5

Two cars, a Maruthi and a Toyato, start at the same time in opposite directions from two distinct points A and B. Starting from A, the Maruthi reaches B in 6 hrs 20 minutes and the Toyato starting from B, reaches A in 4 hrs 45 minutes. What is the s…

Accepted Answer

Let the distance between A and B = D Given the speed of maruthi = 60 kmph Maruthi reaches from A to B in 6 hrs 20 min = 6 + 20/60 = 6 1/3 hrs Now, the distance between A & B = D = speed x time = 60 x 19/3 = 380 kms As the distance is same for toyato also, given time for toyato = 4 hrs 45 min = 4 + 45/60 = 4 3/4 = 19/4 hrs speed of toyato = distance/time = 380/19/4 = 380 x 4/19 = 80 kmph.

Question 6

In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ?

Accepted Answer

A:B = 200 : 169 A:C = 200 : 182 C B = C A × A B 182 200 × 200 169 => 182:169 When C covers 182 m , B Covers 169 m When C covers 350 m , B Covers 169 182 × 350 => 325 m So C beats B by (350 - 325) = 25 m.

Question 7

Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction ?

Accepted Answer

Relative Speed = 5 ¾ - 4 ½ = 1 ¼ Time = 3 ½ h. Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.

Question 8

Ramu rides his bike at an average speed of 45 km/hr and reaches his desitination in four hours. Somu covers the same distance in six hours. If Ramu covered his journey at an average speed which was 9 km/hr less and Somu covered his journey at an ave…

Accepted Answer

Distance travelled by Ramu = 45 x 4 = 180 km Somu travelled the same distance in 6 hours. His speed = 180/6 = 30 km/hr Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr. Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively. Hence difference in the time taken = 0.5 hours = 30 minutes.

Question 9

A man walks at a speed of 2 km/hr and runs at a speed of 6 km/hr. How much time will the man require to cover a distance of 20 1/2 km, if he completes half of the distance, i.e., (10 1/4) km on foot and the other half by running ?

Accepted Answer

We know that Time = Distance/speed Required time = (10 1/4)/2 + (10 1/4)/6 = 41/8 + 41/6 = 287/24 = 11.9 hours.

Question 10

Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ?

Accepted Answer

60(x + 1) = 64x X = 15 60 x 16 = 960 km

Question 11

Two persons start running simultaneously around a circular track of length 600 m from the same point at speeds of 25 kmph and 35 kmph. When will they meet for the first time any where on the track ?

Accepted Answer

Time taken to meet the first time = length of track/relative speed Given the length of the track is 600 m The relative speed = 25 + 35 = 60 kmph = 60 x 5/18 m Therefore Time = 600 25 + 35 5 18 = 600/60 x (18/5) = 36 sec.

Question 12

Radha and Hema are neighbours and study in the same school. Both of them use bicycles to go to the school. Radha’s speed is 8 km/hr whereas Hema’s speed is 10 km/hr. Hema takes 9 minutes less than Radha to reach the school. How far is the school fro…

Accepted Answer

Let the distance between be D km Time taken by radha – Time taken by Hema = 9 mins So D/8 – D/10 = 9/60 hrs D = 6km

Question 13

Tilak rides on a cycle to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 min. more than that of the first case, what is the total distance travelled by him (in km)?

Accepted Answer

Let the distance travelled by Tilak in first case or second case = d kms Now, from the given data, d/20 = d/22 + 36 min => d/20 = d/22 + 3/5 hrs => d = 132 km. Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.

Question 14

In a race of 800m Kaushik gives Piyush a start of 200m and then loses the race by 20 seconds. What is the speed of Piyush and Kaushik respectively ? If the ratio of respective speeds be 3:2.

Accepted Answer

Let the speed of Kaushik be Sk and speed of Piyush be Sp Let the time taken by Piyush be t second then, SkSp = 800t+20600t = 23 Since given ratio t = 20 s Speed of Piyush = Sp = 600/20 = 30 m/s Speed of Kaushik = 800/40 = 20 m/s

Question 15

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds?

Accepted Answer

In the same time, they cover 110 km and 90 km respectively. Therefore, Ratio of their speeds = 110 : 90 = 11 : 9

Question 16

If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ?

Accepted Answer

Let the distance between home and school is 'x'. Let actual time to reach be 't'. Thus, x/4 = t + 4 ---- (1) and x/6 = t - 30 -----(2) Solving equation (1) and (2) => x = 98 mts.

Question 17

K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?

Accepted Answer

let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.

Question 18

Jagan went to another town covering 240 km by car moving at 60 kmph. Then he covered 400km by train moving at 100 kmph and then rest 200 km he covered by a bus moving at 50 kmph. The average speed during the whole journey was ?

Accepted Answer

By car 240 km at 60 kmph Time taken = 240/60 = 4 hr. By train 240 km at 60 kmph Time taken = 400/100 = 4 hr. By bus 240 km at 60 kmph Time taken = 200/50 = 4 hr. So total time = 4 + 4 + 4 = 12 hr. and total speed = 240+400+200 = 840 km Average speed of the whole journey = 840/12 = 70 kmph.

Question 19

An express traveled at an average speed of 100 km/hr, stopping for 4 min after every 75 km. How long did it take to reach its destination 600 km from the starting point ?

Accepted Answer

Time taken to cover 600 km = 600/100 = 6 hrs. Number of stoppages = 600/75 - 1 = 7 Total time of stoppages = 4 x 7 = 28 min Hence, total time taken = 6 hrs 28 min.

Question 20

Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m. ?

Accepted Answer

Let the distance traveled be x km. Then, x/10 - x/15 = 2 3x - 2x = 60 => x = 60 km. Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs. So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m. Required speed = 60/5 = 12 kmph.

Time and Distance Questions