(A + B)'s 1 day's work = |
1 |
10 |
(A + B + C)'s 1 day's work = |
❨ |
1 |
+ |
1 |
❩ |
= |
6 |
= |
3 |
. .... (i) |
10 |
50 |
50 |
25 |
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) = |
3 |
25 |
⟹ A's 1 day's work = |
3 |
. |
50 |
∴ B's 1 day's work |
❨ |
1 |
- |
3 |
❩ |
= |
2 |
= |
1 |
. |
10 |
50 |
50 |
25 |
So, B alone could do the work in 25 days.