Difficulty: Easy
Correct Answer: w l^2 / 10
Explanation:
Introduction / Context:
This question tests the structural design convention for stairs that span longitudinally and are cast integrally with landings. When landings act as supports, the stair slab behaves like a continuous slab, which reduces the midspan bending moment compared to a simply supported case.
Given Data / Assumptions:
Concept / Approach:
For simply supported slabs, the design midspan moment is w l^2 / 8. For continuous slabs with adequate end fixity or continuity, recognized coefficients reduce the midspan moment. A common conservative coefficient for a continuous slab/flight over landings is w l^2 / 10 for the maximum positive moment in the span, acknowledging continuity without performing a full frame analysis.
Step-by-Step Solution:
Model the stair slab as a continuous member over supports at landings.Adopt the standard moment coefficient for a continuous slab: M_max,span ≈ w l^2 / 10.Use this value per metre width for reinforcement design in the flight.
Verification / Alternative check:
Where more accuracy is needed, a continuous-beam analysis (e.g., moment distribution) can be done; the resulting span moments will typically be close to or lower than the w l^2 / 10 coefficient, confirming the conservatism of the rule-of-thumb.
Why Other Options Are Wrong:
w l^2 / 8: Suits simply supported behavior, unconservative for continuous action.w l^2 / 12 or /16: Too small for general continuous stair design without a full analysis.w l^2 / 2: Corresponds to cantilever case; not applicable here.
Common Pitfalls:
Final Answer:
w l^2 / 10
Discussion & Comments