Question 1

The number of odd days in a leap year is?

Accepted Answer

A leap year has (52 week + 2 days). So, the number of odd days in a leap year is 2

Question 2

Number of hours and minutes from 6 : 14 am to 8 : 02 pm on the same days is?

Accepted Answer

Total hours 6 : 14 am morning to evening 6 : 14 pm = 12 h and total hours from 6 : 14 pm evening to 8 : 02 pm evening = 8 : 02 - 6 : 14 = 1 : 18 h i.e., 1 h and 48 min ∴ Total hours and minutes = 12 h + 1 h 48 min = 13 h and 48 min

Question 3

At what time between 3 o'clock and 4 o'clock will the hands of a clock be together?

Accepted Answer

Here, n = 3 and (n + 1) = 4 ∴ Two hands will coincide at 60n / 11 min past n ⇒ 60 x 3 / 11 min past 3 ⇒ 180 /11 min past 3. ⇒ 164/Sub>11 min past 3

Question 4

By which of the following a leap year must be divided

Accepted Answer

A leap year must be divisible by 4 as every 4th year is a leap year..

Question 5

The calendar for the year 2002 is the same as for the year

Accepted Answer

Count the number of odd days from the year 2002 onwards to get the sum equals to 0 odd day. Years 2002 2003 2004 2005 2006 2007 Odd days 1 1 2 1 1 1 Sum = 7 odd days = 0 odd day Calender for the year 2008 is the same as that for the year 2002.

Question 6

Which of following is a leap year?

Accepted Answer

The century year which is completely divisible by 400, is a leap year. Thus, the year 2800 is a leap year.

Question 7

A clock is started at 6 O' clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 11 O' clock in the morning?

Accepted Answer

Angle traced by hour hand in 12 h = 360° Angle traced by hour hand in 5 h = (360/12) x 5° = 150°

Question 8

In an accurate clock, in a period of 2 h 20 min. the minute hand will move over?

Accepted Answer

2 h 20 min = 140 min In every hour the minute hand move over 360°. So, in every minute it will move 360°/60° = 6° So, in 140 min the minute hand will move over = 6 x 140° = 840°

Question 9

The reflection of a clock in the mirror is 3 h 45 min. What is the actual time shown in the clock?

Accepted Answer

The actual time show is 8 h 15 min .

Question 10

The priest told the devotee, 'The temple bell rings at regular intervals of 45 min. The last bell rang 5 min ago. The next bell is due to be rung at 7 : 45 am'. At what time did the priest give this information to the devotee?

Accepted Answer

Pries gave the information to the devotee at 7 :05 am .

Question 11

The number of times in a day the hour hand and the minute hand of a clock are at right angles, is?

Accepted Answer

In every hour the hand of clock are right angles 2 times, so in a days i.e., 24 h they will be at right angle 48 times.

Question 12

If the first day of June is Saturday, them the date on which the last Saturday of that month falls, is?

Accepted Answer

If the first Saturday of June is in lst. Then, next Saturday will be on 8th, 15th , 22nd and 29th. So , last Saturday will be on 29th.

Question 13

At what time between 1 and 2 O' clock are the hands of a clock together?

Accepted Answer

At 1 O' clock the the hour hand is at 1 and the minute hand is at 12. Thus, they are 5 min spaces apart. To be together, the minute hand must gain 5 min over the hour hand . 55 min are gained by minute hand in 60 min. 5 min will be gained by it in = (60/55 x 5 ) = 60/11 = 55/11 min Hence, the hands will coincide at 55/11 min past 1 .

Question 14

How much does a watch lose per day , if its hands coincide every 64 min?

Accepted Answer

Normally, hands of a watch coincide after 655/11 min. So, loss per hour = 15/11 min ∴ Loss per day = 24 x 15/11 = 24 x 16/11 = 3410/11 min

Question 15

The last day of year, 2006 was?

Accepted Answer

Last two digits of year : 06 Divided by 4 :01 Date: 31 (last day will be 31st Dec) Month code : 6 Final value : 44 On dividing by 7, we get 2 as remainder. As year is between 2000 - 2099, so 1 has to be subtracted, now the result = 2 - 1 = 1 1 is the day code for Sunday.

Question 16

At what time between 5 and 5 : 30 is the hands of a clock 5 min apart?

Accepted Answer

At 5 O' clock, the minute hand is 25 min space apart. The two hands will be 5 min apart between 5 and 5 : 30, if the minute hand is (25 - 5) i.e, 20 min spaces behind the hour hand. Now, 55 min are gained in 60 min. 20 min are gained in = (60/55 x 20) = (240/11) = 219/11 min So, the hands will be 5 min apart at 219/11 min past 5.

Question 17

Number of hours and minutes from 6 : 14 am to 8 : 02 pm on the same days is

Accepted Answer

Total hours from 6 : 14 am morning to evening 6 : 14 pm = 12 h and total hours from 6 : 14 pm evening to 8 : 02 pm evening = 8 : 02 - 6 : 14 = 1 : 48 h i.e., 1 h and 48 min ∴ Total hours and minutes = 12 h + 1 h 48 min = 13 h and 48 min

Question 18

By which of the following, a leap year must be divisible?

Accepted Answer

A leap year must be divisible by 4, as every 4th year is a leap year.

Question 19

Which of the following is a leap year?

Accepted Answer

As 2016 is completely divisible by 4.

Question 20

Today is Monday. What will be the day after 64 days?

Accepted Answer

Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday. Hence, after 64 days. it will be Tuesday.

Calendar Questions