Question 1

How often between 11 O'clock and 12 O'clock are the hands of a clock in integral number of minutes apart?

Accepted Answer

As per the given above question , we can say that At 11 O'clock, the hour hand is 4 spaces apart from the minute hand. Since there are 60 spaces in one hour, so (60 - 4) times, i.e., 56 times the hands of the clock are an integral number of minutes apart. Hence , required answer is 56 times .

Question 2

Number of times the hands of a clock are in a straight line everyday is:

Accepted Answer

We know that, any relative position of the hands of a clock is repeated 11 times in every 12 hours. ∴ In every 12 hours, hands coincide 11 times and are opposite to each other 11 times. ∴ In every 12 hours, hands are in a straight line 11 + 11 = 22 times. ∴ In every 24 hours hands are in a straight line 44 times.

Question 3

The watch which gains uniformly is 2 minutes. slow at noon on Sunday and is 4 minutes. 48 seconds. fast at 2 pm on the following Sunday. The watch was correct at:

Accepted Answer

Question 4

Number of times 29th day of the month occurs in 400 consecutive years is:

Accepted Answer

On the basis of above given question , we know that 400 consecutive years contain 97 leap years. ∴ In 400 consecutive years February has 29 days 97 times and the remaining 11 months have 29th day 400 × 11 = 4400 times ∴ 29th day of the month occurs ( 4400 + 97 ) = 4497 times.

Question 5

If March 2, 1994 was on Wednesday, January 1994 25, was on:

Accepted Answer

As per the above given question , we can say that Number of days from January 25, 1994 to March 2, 1994 is January + February + March = 6 + 28 + 2 = 36 days = 5 weeks + 1 odd day ∴ Number of odd days = 1 ∴ Day on January 25, 1994 is one day before the day on March 2, 1994. But March 2, 1994 was on Wednesday. Therefore , January 1994 25 was on Tuesday

Question 6

If a clock strikes 6 times in five seconds, the number of strikes in 10 seconds is:

Accepted Answer

Question 7

Suresh was born on October 4, 1999. Shashikanth was born 6 days before Suresh. The Independence day of that year fell on Sunday. Which day was Shashikanth born?

Accepted Answer

As per the given above question , we have Birth date of Sashikant = September 28 Difference in number of days from August 15 to September 28 = 16 + 28 = 44 Number of odd days in 44 days = 2 odd days Hence , Birthday of Shashikant = Sunday + 2 odd days = Tuesday.

Question 8

A wall clock gains 2 minutes in 12 hours, while a table clock loses 2 minutes every 36 hours. Both are set right at 12 noon on Tuesday. The correct time when both show the same time next would be:

Accepted Answer

Question 9

In every 30 minutes the time of a watch increases by 3 minutes. After setting the correct time at 5 am, what time will the watch show after 6 hours?

Accepted Answer

As per the given above question , we can say that In 1 hour it increases by 6 minutes so in 6 hours it increases by 36 minutes. Thus , required time will be 11 : 42 am .

Question 10

A man who went out between 3 and 4 and returned between 8 and 9, found that the hands of the watch had exactly changed places. He returned at:

Accepted Answer

As per the given above question , we can say that 1. In 1 min ,minute hand moves 6 Degree 2. In 1 min,hour hand moves 0.5 Degree Let suppose man went out at y past three i.e. 3 hours y minutes then, minute hand will be at ( 6y ) Degree from origin. and hour hand will be at ( 3 × 30 + y × 0.5) Degree = ( 90 + 0.5y ) Degree Similarly ,man returned at z past eight i.e. 8 hours z minutes then, minute hand will be at ( 6z ) Degree from origin. and hour hand will be at ( 8 × 30 + z × 0.5 ) Degree = ( 240 + 0.5z ) Degree And as per the given condition :- 6y = 90 + 0.5y ...... ( ⅰ ) and 6z = 240 + 0.5z ...... ( ⅱ ) Solve these equations , we get y = 16.36 and z =43.63

Question 11

At what time between 4 : 30 and 5 will the hands of a clock be in a straight line?

Accepted Answer

Question 12

How often are the hands of a clock at right angle everyday?

Accepted Answer

We know that , In every hour there are two positions in which hands are at right angle. Each of these positions is repeated 11 times in every 12 hours. ∴ In every 12 hours, hands are at right angles 11 + 11 = 22 times and in a day hands are at right angles 22 + 22 = 44 times. Hence , required answer will be 44 times.

Question 13

How many times do the hands of a clock point towards each other in a day?

Accepted Answer

According to question , we know that The hands of a clock point towards each other 11 times in every 12 hours. (because between 5 and 7, at 6 O'clock only they point towards each other) So, in a day the hands point towards each other 22 times. Hence , correct answer will be 22 times.

Question 14

Mahatma Gandhi was born on October 2, 1869. The day of the week was:

Accepted Answer

Question 15

On what date of August, 1988 did Friday fall?

Accepted Answer

We can say that , August 1, 1988 means = 1987 years + 7 months Number of odd days in 1987 years = 1600 years have 0 odd days + 300 years have 1 odd day + 87 years have 21 leap years and 66 ordinary years. So, there are [ ( 21 × 2 ) + ( 66 × 1 ) ] = 108 days, = 15 weeks and 3 odd days. Number of days between January 1, 1988 to August 1, 1989 = January + February + March + April + May + June + July + August = 31 + 29 + 31 + 30 + 31 + 30 + 31 + 1 = 241 days = 30 weeks and 4 odd days. Total number of odd days = 0 + 1 + 3 + 4 = 8 odd days = ( 1 x 7 + 1 ) = 1 odd day. Thus, Friday falls on 5th, 12th, 19th and 26th in August 1988.

Question 16

The year next to 1991 having the same calender as that of 1990 is?

Accepted Answer

We go on counting the odd day from 1991 onwards till the sum is divisible by 7 . The number of such days are 14 up to the year 2001. So, the calendar for 1991 will be repeated in the year 2002.

Question 17

Smt. Indira Gandhi died on 31st october, 1984. The day of the week was?

Accepted Answer

1600 years contains 0 odd day; 300 years conains 1 odd day. Also, 83 years contains 20 leap years and 63 ordinary years and therefore, (40 + 0) odd days i.e., 5 odd days. ∴ 1983 years contain (0 + 1 + 5) i.e., 6 odd days Number of days from Jan. 1984 to 31st Oct 1984 = (31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31) = 305 days = 4 odd days ∴ Total number of odd days = 6 + 4 = 3 odd days So, 31st Oct 1984 was wednesday

Question 18

January 16, 1997 was a Thursday. What day of the week will it be on January 4, 2000?

Accepted Answer

First we look for the leap years during this period 1997, 1998, 1999 are not leap years. 1998 and 1999 together have net 2 odd days No. of days remaining in 1997 = 365 - 16 = 349 days = 49 week 6 odd days January 4, 2000 gives 4 odd days. ∴ Total no. of days = 2 + 6 + 4 = 12 days = 7 Days (1 week) + 5 odd days Hence, January 4, 2000 will be 5 days beyond Thursday i.e., it will on Tuesday.

Question 19

P.V. Narsihma Rao was elected party leader on 29th may, 1991. What was the day of the week?

Accepted Answer

Try yourself. It was Wednesday.

Question 20

A clock is set right at 10 am. The clock gain 10 min in a day. What will be the true time when the watch indicates 3 pm the next day?

Accepted Answer

Time from 10 am to 3 pm of the next day = 29 h Now, 24 h 10 min of the clock in question = 24 h of the correct clock i.e., 145 h of the clock in question = 24 h of the correct clock 29 h of the clock in question = 24 x (6/145) x 29) h of correct clock = 28 h 48 min correct clock So, the correct time is 28 h 48 min after 10 am i.,e 48 min past 2 pm.

Calendar Questions