Question 1

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

Accepted Answer

Sunday

Question 2

The calendar for the year 2013 was the same as the year :

Accepted Answer

Given year, 2013 when divided by 4 leaves a remainder of 1. NOTE: When the remainder is 1, 11 is substracted from the given year to get the result. So, 2013 - 11 =2002

Question 3

Which calendar was used again in the year 1856?

Accepted Answer

Given year 1856, when divided by 4 leaves a remainder of 0. NOTE: When remainder is 0, 28 is subtracted to the given year to get the result. So, 1856 - 28 = 1828

Question 4

Which of the following years have 366 days?

Accepted Answer

NOTE: When an year leaves a remainder 0 when divided by 4,then it is a leap year. Here, 1984 divided by 4 leaves a remainder 0. So, answer 1984 (366 days => leap year)

Question 5

Which century year is a leap year?

Accepted Answer

NOTE: For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year. So, 1600

Question 6

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

Accepted Answer

On 31st December, 2005 it was Saturday. Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. therfore, on 31st December 2009, it was Thursday. Thus, on 1st Jan, 2010 it is Friday

Question 7

On what dates of April, 2001 did Wednesday fall ?

Accepted Answer

4th, 11th, 18th, 25th

Question 8

What was the day on 25th Jan,1981?

Accepted Answer

25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981) Odd days in 1600 years = 0 Odd days in 300 years = 1 80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days Jan = 25 days = (3 weeks + 4 days) = 4 odd days. Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day. Given day is Sunday.

Question 9

Oct 1st 1994 falls on which day?

Accepted Answer

1 Oct, 1994 = (1993 years + Period from 1.1.1993 to 1.10.1993) Odd days in 1600 years = 0 Odd days in 300 years = 1 93 years = (70 ordinary years + 23 leap year) = (70 x 1 + 23 x 2)= 4 odd days Jan Feb March April May June July Aug sept Oct (31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 1 ) = 274 days 274 days = (39 weeks + 1 day) =1 odd day. Total number of odd days = (0 + 1 + 4 + 1) = 6 odd days. Given day is Saturday.

Question 10

What was the day of the week on 17th June, 1998?

Accepted Answer

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = (5 x 3) 1 97 years has 24 leap years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days. Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day. Total number of odd days = (0 + 1 + 2 + 0) = 3. Given day is Wednesday

Question 11

How many days are there in k weeks k days ?

Accepted Answer

As we know that a week has 7 days, k weeks k days = (7k + k) days = 8k days.

Question 12

Akarsh's birthday is on Saturday 29th July. On what day of the week will be Ojas's Birthday in the same year if Ojas was born on 12th August?

Accepted Answer

Saturday

Question 13

If 5th January 2011 was a Thursday, then what day of the week was it on 1st January 2013 ?

Accepted Answer

Wednesday

Question 14

On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006 ?

Accepted Answer

Friday

Question 15

The last day of a century cannot be

Accepted Answer

Tuesday

Question 16

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

Accepted Answer

The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004. Given that, 6th March, 2005 is Monday. 6th March, 2004 is Sunday (1 day before to 6th March, 2005).

Question 17

The calendar of the year 2006 was used before in the year?

Accepted Answer

Given year 2006, when divided by 4 leaves a remainder of 2. NOTE: When remainder is 2, 11 is subtracted to the given year to get the result. So, 2006 - 11 = 1995

Question 18

Which of the following year is a leap year?

Accepted Answer

NOTE: For a century year,it is divided by 400 and leaving a ramainder of 0 results a leap year. So,2400 when divided by 400 leaves a remainder 0.

Question 19

What was the day on 31st Dec,2011 ?

Accepted Answer

31st Dec, 2011 = (2010 years + Period from 1.1.2011 to 31.12.2011) Odd days in 2000 years = 0 10 years has 2 leap years + 8 ordinary years. Number of odd days in 10 years ( 2 x 2 + 8) = 5 odd days. 31st,Dec => complete year of 2011 (non-leap year) = 1 odd day. Total number of odd days = (0 + 5 + 1) = 6. Given day is saturday.

Question 20

Karan remembers that his sister's birthday is not after 18th August. Karan's mother remembers that Karan's sister birthday is before 20th August but after 17th August. On which date of August is Karan's sister birthday?

Accepted Answer

18

Calendar Questions