Question 1

The calendar for the year 1993 will be same for the year

Accepted Answer

NOTE : Repetition of leap year ===> Add +28 to the Given Year. Repetition of non leap year Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2. Step 2: Add +6 to the Given Year. Solution : Given Year is 1993, Which is a non leap year. Step 1 : Add +11 to the given year (i.e 1993 + 11) = 2004, Which is a leap year. Step 2 : Add +6 to the given year (i.e 1993 + 6) = 1999 Therfore, The calendar for the year 1993 will be same for the year 1999

Question 2

How many leap years do 300 years have?

Accepted Answer

Given year is divided by 4, and the quotient gives the number of leap years. Here, 300%4 = 75. But, as 100,200 and 300 are not leap years => 75 - 3= 72 leap years.

Question 3

The calendar for the year 2018 will be the same for the year

Accepted Answer

How to find the years which have the same Calendars : Leap year calendar repeats every 28 years. Here 28 is distributed as 6 + 11 + 11. Rules: a) If given year is at 1st position after Leap year then next repeated calendar year is Given Year + 6. b) If given year is at 2nd position after Leap year then next repeated calendar year is Given Year + 11. c) If given year is at 3rd position after Leap year then next repeated calendar year is Given Year + 11. Now, the given year is 2018 We know that 2016 is a Leap year. 2016 2017 2018 2019 2020 LY 1st 2nd 3rd LY Here 2018 is at 2 nd position after the Leap year. According to rule ( b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.

Question 4

Prove that any date in March of a year is the same day of the week corresponding date in November that year.

Accepted Answer

We will show that the number of odd days between last day of February and last day of October is zero. . March April May June July Aug. Sept. Oct. 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 = 241 days = 35 weeks = 0 odd day. ,Number of odd days during this period = 0. Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows

Question 5

The calendar for the year 1988 is same as which upcoming year ?

Accepted Answer

We already know that the calendar after a leap year repeats again after 28 years. Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.

Question 6

If yesterday were tomorrow, then today would be Friday. What day is today?

Accepted Answer

If yesterday were tomorrow, today is Friday => tomorrow of friday is Saturday. Hence, it implies that today is Sunday if tomorrow is Saturday.

Question 7

What was the day of the week on 16th August, 1947?

Accepted Answer

15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th ) Counting of odd days: 1600 years have 0 odd day. 300 years have 1 odd day. 47 years = (11 leap years + 36 ordinary years)= [(11 x 2) + (36 x 1) ]odd days = 58 odd days = 2 odd days. Jan Feb Mar Apr May Jun Jul Aug. 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 days = (32 weeks + 3 days) = 3, Total number of odd days = (0 + 1 + 2 + 3) odd days = 6 odd days. Hence, the required day was 'Saturday'.

Question 8

If July 9th,2013 falls on Sunday then Jan 7th,2014 falls on which day?

Accepted Answer

First,we count the number of odd days for the left over days in the given period.Here,given period is 09-07-2013 to 07-01-2014 Month Jul Aug Sep Oct Nov Dec Jan Days 22 31 30 31 30 31 7 Odd Days 1 3 2 3 2 3 0 Therefore, No. of Odd Days = 1 + 3 + 2 + 3 + 2 + 3 + 0 = 14 = 0 odd days So, given day Sunday + 0 = Saturday is the required result.

Question 9

The year next to 2005 will have the same calendar as that of the year 2005?

Accepted Answer

NOTE : Repetition of leap year ===> Add +28 to the Given Year. Repetition of non leap year Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2. Step 2: Add +6 to the Given Year. Solution : Given Year is 2005, Which is a non leap year. Step 1 : Add +11 to the given year (i.e 2005 + 11) = 2016, Which is a leap year. Step 2 : Add +6 to the given year (i.e 2005 + 6) = 2011 Therfore, The calendar for the year 2005 will be same for the year 2011

Question 10

Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?

Accepted Answer

Given that the month begins on a Friday and has 31 days Sundays = 3rd, 10th, 17th, 24th, 31st => Total Sundays = 5 Every second & fourth Saturday is holiday. 2nd & 4th Saturday in every month = 2 Total days in the month = 31 Total working days = 31 - (5 + 2) = 24 days.

Question 11

If today is Saturday, what will be the day 350 days from now ?

Accepted Answer

350 days = (350/7=50 weeks) i.e No odd days, So it will be a Saturday.

Question 12

The calendar of the year 2024 can be used again in the year?

Accepted Answer

NOTE : Repetition of leap year ===> Add +28 to the Given Year. Repetition of non leap year Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2. Step 2: Add +6 to the Given Year. Solution : Given Year is 2024, Which is a leap year. So, Add +28 to the given year (i.e 2024 + 28) = 2052 Therfore, The calendar of the year 2024 can be used again in the year 2052.

Question 13

How old are you if you are born in 1995?

Accepted Answer

Calculating Age has 2 conditions. Let your Birthday is on January 1st. 1. If the month in which you are born is completed in the present year i.e, your birthday, then Your Age = Present year - Year you are born As of now, present year = 2018 i.e, Age = 2018 - 1995 = 23 years. 2. If the month in which you are born is not completed in the present year i.e, your birthday, then Your Age = Last year - Year you are born As of now, present year = 2018 i.e, Age = 2017 - 1995 = 22 years.

Question 14

What is two weeks from today?

Accepted Answer

We know that the day repeats every 7 days, 14 days, 21 days,... So if today is Monday, after 7 days it is again Monday, after 14 days again it is Monday. Hence, after 2 weeks i.e, 14 days the day repeats and is the same day.

Question 15

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010 ?

Accepted Answer

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. On 1st Jan 2006, it was Sunday. Thus, On 1st Jan, 2010 it is Friday.

Question 16

How many seconds in 10 years?

Accepted Answer

We know that, 1 year = 365 days 1 day = 24 hours 1 hour = 60 minutes 1 minute = 60 seconds. Then, 1 year = 365 x 24 x 60 x 60 seconds. = 8760 x 3600 1 year = 31536000 seconds. Hence, 10 years = 31536000 x 10 = 315360000 seconds.

Question 17

Suppose today is Friday, what day of the week will it be 65 days from now?

Accepted Answer

The day of the week repeats every 7 days. Given today is Friday. Again Friday is repeated on the 7th day, 14th,... on 7 multiple days. Hence, Friday is on the 63rd day, as 63 is multiple of 7. Now, the required day of the week on the 65th day is Sunday.

Question 18

Given that on 9th August 2016 is Saturday. What was the day on 9th August 1616 ?

Accepted Answer

We know that, After every 400 years, the same day occurs. Thus, if 9th August 2016 is Saturday, before 400 years i.e., on 9th August 1616 has to be Saturday.

Question 19

How many weekends in a year?

Accepted Answer

Weekend means Saturday & Sunday together. In total we have 52 weeks in a year. So there are 52 weekends in a year. In normal we have 104 Weekend Days. We know that a Each normal year has 365 days or 52 weeks plus one day, and each week has two weekend days, which means there are approximately 104 weekend days each year. Whereas in a leap year we have 366 days it adds one more day to the year. And what makes the change is the starting day of the year.

Question 20

Which of the following is not a leap year?

Accepted Answer

Leap year means the year that can be divisible by 4. From the above options 2009 is not divisible by 4. So it is not a leap year.

Calendar Questions