Question 1

What was the day of the week on, 16th July, 1776?

Accepted Answer

16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776) Counting of odd days : 1600 years have 0 odd day. 100 years have 5 odd days. 75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days 1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day. Jan Feb Mar Apr May Jun Jul 31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days) Total number of odd days = (0 + 2) = 2. Required day was 'Tuesday'.

Question 2

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

Accepted Answer

On 31st December, 2005 it was Saturday. Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days. On 31st December 2009, it was Thursday. Thus, on 1st Jan, 2010 it is Friday

Question 3

What was the day of the week on 28th May, 2006?

Accepted Answer

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006) Odd days in 1600 years = 0 Odd days in 400 years = 0 5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) = 6 odd days (31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 dayss = (21 weeks + 1 day) = 1 odd day. Total number of odd days = (0 + 0 + 6 + 1) = 7 = 0 odd days. Given day is Sunday

Question 4

How many days are there in x weeks x days?

Accepted Answer

x weeks x days = (7x + x) days = 8x days.

Question 5

What will be the day of the week 15th August, 2010?

Accepted Answer

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010) Odd days in 1600 years = 0 Odd days in 400 years = 0 9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days. Jan. Feb. Mar. Apr. May. Jun. Jul. Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days. Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days. Given day is Sunday

Question 6

What was the day of the week on 17th June, 1998 ?

Accepted Answer

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = 1 97 years has 24 leap years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days. Jan. Feb. March. April. May. June. (31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day. Total number of odd days = (0 + 1 + 2 + 0) = 3. Given day is Wednesday.

Question 7

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

Accepted Answer

The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004. Given that, 6th March, 2005 is Monday. 6th March, 2004 is Sunday (1 day before to 6th March, 2005).

Question 8

On what dates of April, 2001 did Wednesday fall?

Accepted Answer

We shall find the day on 1st April, 2001. 1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001) Odd days in 1600 years = 0 Odd days in 400 years = 0 Jan. Feb. March April (31 + 28 + 31 + 1) = 91 days 0 odd days. Total number of odd days = (0 + 0 + 0) = 0 On 1st April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.

Question 9

Which two months in a year have the same calendar?

Accepted Answer

If the period between the two months is divisible by 7, then that two months will have the same calender . (a). Oct + Nov = 31 + 30 = 61 (not divisible by 7) (b). Apr + May + Jun + Jul + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31 = 214 (not divisible by 7) (c). Jun + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7) (d). Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7) Hence, April and July months will have the same calendar.

Question 10

On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?

Accepted Answer

The year 2006 is an ordinary year. So, it has 1 odd day. So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006. But, 8th Dec, 2007 is Saturday S0, 8th Dec, 2006 is Friday.

Question 11

The maximum gap between two successive leap year is?

Accepted Answer

This can be illustrated with an example. Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).

Question 12

If Aug 15th,2012 falls on Thursday then June 11th,2013 falls on which day ?

Accepted Answer

First,we count the number of odd days for the left over days in the given period. Here,given period is 15.8.2012 to 11.6.2013 Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun 16 30 31 30 31 31 28 31 30 31 11(left days) 2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days So,given day Thursday + 6 = Wednesday is the required result.

Question 13

26 january 1950 which day of the week?

Accepted Answer

We know that, Odd days --> days more than complete weeks Number of odd days in 400/800/1200/1600/2000 years are 0. Hence, the number of odd days in first 1600 years are 0. Number of odd days in 300 years = 1 Number of odd days in 49 years = (12 x 2 + 37 x 1) = 61 days = 5 odd days Total number of odd days in 1949 years = 1 + 5 = 6 odd days Now look at the year 1950 Jan 26 = 26 days = 3 weeks + 5 days = 5 odd days Total number of odd days = 6 + 5 = 11 => 4 odd days Odd days :- 0 = sunday ; 1 = monday ; 2 = tuesday ; 3 = wednesday ; 4 = thursday ; 5 = friday ; 6 = saturday Therefore, Jan 26th 1950 was Thursday.

Question 14

If Feb 12th,1986 falls on Wednesday then Jan 1st,1987 falls on which day?

Accepted Answer

First,we count the number of odd days for the left over days in the given period. Here,given period is 12.2.1986 to 1.1.1987 Feb Mar Apr May June July Aug Sept Oct Nov Dec Jan 16 31 30 31 30 31 31 30 31 30 31 1 (left days) 2 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 1(odd days) = 1 odd day So,given day Wednesday + 1 = Thursday is the required result.

Question 15

January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

Accepted Answer

The year 2007 is an ordinary year. So, it has 1 odd day. 1st day of the year 2007 was Monday 1st day of the year 2008 will be 1 day beyond Monday Hence, It will be Tuesday.

Question 16

How many leap years does 100 years have?

Accepted Answer

Given year is divided by 4, and the quotient gives the number of leap years. Here, 100%4 = 25. But, as 100 is not a leap year => 25 - 1= 24 leap years.

Question 17

On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?

Accepted Answer

The year 2004 is a leap year. It has 2 odd days. The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005. Hence, this day is Sunday

Question 18

The calendar for the year 2007 will be the same for the year

Accepted Answer

2018

Question 19

If Mar 18th,1994 falls on Friday then Feb 25th,1995 falls on which day?

Accepted Answer

First,we count the number of odd days for the left over days in the given period.Here,given period is 18.3.1994 to 25.2.1995 Month Mar Apr May Jun Jul Aug Sep Oct Nov Dec Jan Feb Days 13 30 31 30 31 31 30 31 30 31 31 25 Odd Days 6 2 3 2 3 3 2 3 2 3 3 4 Therefore, No. of Odd Days = 6 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 3 + 4 = 36 = 1 odd day So, given day Friday + 1 = Saturday is the required result.

Question 20

On what dates of July.2004 did Monday fall?

Accepted Answer

Let us find the day on 1st July, 2004. 2000 years have 0 odd day. 3 ordinary years have 3 odd days. Jan. Feb. March April May June July 31 + 29 + 31 + 30 + 31 + 30 + 1 = 183 days = (26 weeks + 1 day) = 1 t . Total number of odd days = (0 + 3 + 1) odd days = 4 odd days. ' :. 1st July 2004 was 'Thursday',-,- Thus, 1st Monday in July 2004 _as on 5th July. Hence, during July 2004, Monday fell on 5th, 12th, 19th and 26th. .

Calendar Questions