Question 1

If 5 th march of a particular year is Friday then which day of the week will be on 5 th November.

Accepted Answer

Here we have to find the number of odd days between, 5th march and 5th November, Number of days in March is 26 or 5 odd days (Here we have not included 5th march) Number of days in April is 30 or 2 odd days Number of days in May is 31 or 3 odd days Number of days in June is 30 or 2 odd days Number of days in July is 31 or 3 odd days Number of days in August is 31 or 3 odd days Number of days in September is 30 or 2 odd days Number of days in October is 31 or 3 odd days Number of days in November is 5 or 5 odd days (Here 5th November is included) So total number of odd days = 5 + 2 + 3 + 2 + 3 + 3 +2 + 3 + 5 = 28 when divided by 7 gives remainder 0 hence 5th November will be same as that of 5th march.

Question 2

How many weekends are there in March 2009?

Accepted Answer

From Zeller's Formula we can find that 1st March 2009 is Sunday so well have 5 Saturdays and 5 Sundays in total 10 weekends.

Question 3

Which of the following two months in a particular year will have same calendar.

Accepted Answer

January and August or October depends on leap year or non leap year. But if we find the number of odd days between March and November we will get number of odd days is 0 hence they will have same calendar.

Question 4

On 14 th Feb the valentine day, 2009 it was Saturday. What was the day of the week on 14 th Feb, 2008?

Accepted Answer

The year 2008 is a leap year. It has 2 odd days. The day on 14th feb, 2008 is 2 days before the day on 14th Feb 2009. Hence this day is Thursday.

Question 5

How many days could be in K weeks and K days.

Accepted Answer

Number of days in K weeks is 7K hence total number of days is 7K + K = 8k or number of days must be a multiple of 8.

Question 6

How many days are between K th day of the K th week to 2K th day of the 2K th week

Accepted Answer

Number of days in K weeks is 7K hence total number of days is 7K + K = 8k Similarly number of days in 2Kth day of the 2Kth week is 2k x 7 + 2k = 16k Required number of days is 16K - 8K = 8K or number of days must be a multiple of 8.

Question 7

Find the angle between minute hand hour hand at 6 : 30 AM

Accepted Answer

At 6 : 30 A.M. from the formula here P = 6 and Q = 30 so required angle is 11 x 30/2 - 30 x 6 = 165 - 180 = - 15 or ignoring the negative sign the required angle is 15°

Question 8

The last day of century cannot be either I. Tuesday II. Thursday III. Saturday IV. Sunday

Accepted Answer

The last day of century cannot be either Tuesday, Thursday or Saturday.

Question 9

Mrs Susheela celebrated her wedding anniversary on Tuesday, 30th September, 1997. When will she celebrate her next wedding anniversary on the same day?

Accepted Answer

Total number of odd days 30 September, 1997-98 = 1 30 September, 1998-99 = 1 30 September, 1999-2000 = 2 30 September, 2000-02 = 1 30 September, 2001-02 = 1 30 September, 2002-03 = 1/7 ∴ Tuesday + 7 = Tuesday So, the next Tuesday will come on the Mrs Susheela's wedding anniversary in 30th September, 2003

Question 10

If Republic day was celebrated in 1996 on Friday, on which day in 2000 Independence was celebrated?

Accepted Answer

26 January, 1996 to 15 August, 2000 days were = 1663 1663 having odd day = 4 ∴ In the year 2000, Independence day will on Tuesday.

Question 11

If 18th February, 1997 falls on Tuesday, then what will be the day on 18th February, 1999?

Accepted Answer

18th February, 1997 is Tuesday. So, 17th February, 1998 will also be Tuesday. Again 16th February, 1999 will also be Tuesday. Hence, 18th February, 1999 will be Thursday.

Question 12

I was born on August 11. Mohan is younger to me by 11 days. This year's independence day falls on Monday. The day on which Mohan's birthday will fall this year will be

Accepted Answer

Mohan was born on 31st July, August 15 falls on Monday.

Question 13

At what time, (in minutes) between 3 O'clock, and 4 O'clock, both the needles will coincide with each other?

Accepted Answer

At 3 O'clock, then minute hand is 15 min away from the hour hand. To coincide, it must gain 15 min as 55 min are gained in 60 min. 15 min are gained in (60/55) x 15 min = 164/11 min Hence, the hands are coincide at 164/11 min past 3.

Question 14

A clock is set right at 5 am. The clock loss 16 min in 24 h. What will be the right time when the clock indicates 10 Pm on the third day?

Accepted Answer

Time from 5 am of a particular day to 10 pm on the 4th day is 89 h. Now, the clock loses 16 min in 24 h or on other words, we can say that 23 h 44 min of this clock is equal to 24 h of the correct clock. or (23 + 44/60) ⇒ 356 h of this clock = 24 h of the correct clock ∴ 89 h of this clock = (24 x 15/356 x 89) h of correct clock = 90 h of the correct clock

Question 15

The Republic day of India was celebrated on Friday in year 2008. On which day, it will be celebrated in 2012?

Accepted Answer

26th January (Republic day) 2008 → Friday Clary, it will be on Wednesday in 2012.

Question 16

If 8th February, 2005 was a Tuesday, what was the day the 8th February,2004?

Accepted Answer

The year 2004 is a leap year. It has 2 odd days. The day on 8th February, 2004 is 2 days before the day on 8th February, 2005. Hence, this day is Sunday

Question 17

What was the day the 2nd July, 1984?

Accepted Answer

2nd July, 1984 means (1983 years 6 months and 2 days) 1900 years have 1 odd day 83 years have 20 leap years and 63 ordinary years = (40 + 63) odd days = 103 = 5 odd days 6 months and 2 days Jan 31 Feb 29 Mar 31 Apr 30 May 31 June 30 July 02 = 184 days = 2 odd days Total number of days = (1 + 5 + 2) = 8 odd days = 1 odd day Hence, it was Monday on 2nd July,1984.

Question 18

The year next to 1990 will have the same calender as that of the year 1990.

Accepted Answer

The year 1990 has 356 days, i.e., 1 odd day, year 1991 has 356 days, v 1 odd day, year 1992 has 366 days, i.e., 2 odd days. Likewise year 1993, 1994, 1995 have 1 odd days, so calculated from years 1990-95 = (1 + 1 + 2 + 1 + 1 + 1) = 7 odd days = 0 odd day Hence, the year 1996 will have the same calendar as that of the year 1990.

Question 19

If 27 March, 1995 was a Monday, then what day of the week was 1 November, 1994?

Accepted Answer

Here, 27th March 1995 was Monday. Now for calculating total number of odd days. First, we calculate total number of days till 1 Number 1994 ∴ Number of days in March 1995 = 27 Number of days in February 1995 = 28 Number of days in January 1995 = 31 Number of days in December 1994 = 31 Number of days in November 1994 = 29/146 ∴ Number of odd days = 146/7 = 206/7 So, 6 odd days. ∴ On November 1, 1994 = Monday - 6 = Tuesday

Question 20

If it was Saturday on December 17, 1899, what will be the day on December 22,1901?

Accepted Answer

Total number of odd days from December 17, 1899 to December 22, 1901 14 + 356 + 356 = 735 or, 735/7 = 105 = 0 odd days it was Saturday on December 17, 1899. So, it will be Saturday on December 22, 1901.

Calendar Questions